You didn't create a new type in int *. You didn't create a new type in int []. Since you didn't create it, it's not a struct type. Only you can create structs.
You didn't create a new type in int *. You didn't create a new type in int []. Since you didn't create it, it's not a struct type. Only you can create structs.
thanks i think i understood this struct thing
what this line means
i know that ! means differ but here they didnt mentionCode:if(!tree)return NULL;
differ what??
Simple boolean magic.
Basic rules:
0 is false. Always.
Everything else is true. Always.
Basic if form:
if (!tree == true)
Let us assume that tree contains a value of NULL.
Thusly, tree is interpreted as false in boolean form (since NULL is one way or another 0).
Thus, we get:
if (!false == true)
The ! operator will invert the meaning of the value it is applied to, so we get:
if (true == true)
Or in other words, it's a short-hand for:
if (tree == NULL)
Last edited by Elysia; 10-27-2008 at 03:37 PM.
Originally Posted by Adak
ok i understood this "!" thing
igot problem understanding something else
its a complex variable
inside this node variable we have two sub variables
data (which can be null or not)
so is the sub variable next
those two different sub variable
we cant see them as one
i dont know what the meaning of tree=null
regarding its subvariables
??
Last edited by transgalactic2; 10-27-2008 at 03:27 PM.
true and tree being in the same conditional statement is hard for my simpleton brain to wrap around.
See them as one what? They already are one node.
what are the values of root.data and root.next
when we do
Code:root=null;
Code:if(!root) { /* Not messing with members of root goes here!!!!! */ }
NULL pointers, as they are commonly referred to. Pointers pointing to "nothing."
They cannot be dereferenced, but it is an easy way to tell if they point to something valid or not.
root is a pointer. It is not a struct.
when we are doing
root=null
we treat it as if it was a simple variable
but its not
what are the values of root.data and root.nextCode:root=null;
when we do
That's because it is. It is a pointer.
Again, and in english instead of C this time. If root is NULL (or root has NO value) then do NOT be trying to access its members. Unless the original question was how do I generate a seg fault with little effort, in which case be my guest, sport.
but its of a complex type
so i guess
it puts null on every sub variable of this type
Updated example. Better now?
