Thread: Can some 1 debug this for me and help me print the output

> # gone==-gone does not check to see if gone is negative, it checks (in a very roundabout way) to see if gone is zero.
Unless you happen to be using a 1's complement machine, in which case it means something else

Originally Posted by tabstop

I fail to see how using a one's complement machine will change the rules of mathematics.

Possibly because there are two representations for zero in one's complement arithmetic, hence +0 != -0. Then again, I have never had the chance to actually use an implementation that uses one's complement.

+0 and -0 have separate representations, so I don't see how they would compare equal.

Oh, better yet, in section 6.2.6.2, C99 says that "it is unspecified whether these cases actually generate a negative zero or a normal zero, and whether a negative zero becomes a normal zero when stored in an object." Here, "these cases" refer to the use of certain operators like unary + and unary - which may generate a negative zero if the implementation supports negative zeros.

Consequently, whether +0 != -0 in one's complement in a C program is implementation defined.

heres the new code

Code:

int main()
{
	//Define Varibles int and floats
	int gone,gtwo,gthree,gfour,gfive,gsix,gseven,geight,gnine,gten,counter,avg,sum;
	
	
	
	//User Input
	printf("Please enter the 10 grades, make sure you space and use commas to differentiate each grade  ");
	scanf("%i,%i,%i,%i,%i,%i,%i,%i,%i,%i",&gone,&gtwo,&gthree,&gfour,&gfive,&gsix,&gseven,&geight,&gnine,&gten);
	
	
	
	//Check Input
	if (gone >= 0||gtwo >= 0||gthree >= 0||gfour >= 0||gfive >= 0||gsix >= 0||gseven >= 0||geight >= 0||gnine >= 0||gten >=0)
	{
		sum = gone+gtwo+gthree+gfour+gfive+gsix+gseven+geight+gnine+gten;
		avg = sum/10;
	
		
		for(counter=1; counter <=10; counter++)
			{
			counter = counter;
			printf("%i\t%i\n",counter,gone,gtwo,gthree,gfour,gfive,gsix,gseven,geight,gnine,gten);
			}
	}
	else 
	{
		printf("Please enter a positive grade. Grades can not be negative");
		
	}
	
	printf("%i\t%i\t%i",counter,avg,sum);
	
	getch();
	

	return 0;
}

but i need my program to loop and the output to look like this
number of quizzes quiz grade
1 80
2 82
3 50
4 90
5 78
6 90
7 100
8 35
9 11
10 65

It would REALLY help your case if you used arrays instead of individual variables. However, we can do both, I suppose:

Code:

int *ptrArr[] = { &gone,&gtwo,&gthree,&gfour,&gfive,&gsix,&gseven,&geight,&gnine,&gten };
int i;

...
for(i = 0; i < sizeof(ptrArr)/sizeof(ptrArr[0]); i++)
{
   printf("%d\t\%d\n", i, *ptrArr[i]);
}

There, problem solved.

[Of course, your professor will know immediately that you didn't come up with this yourself, at least if he asks you to explain what the code does, so you are probably better off working out how to solve it yourself].

--
Mats

--
Mats