Thread: assigning a memory address to a pointer

Normally an address is assigned to a pointer this way:

Code:

int X, *ptr=&X;

How can I assign the address from a string literal, Eg.

Code:

#define addr "0xbfe146bc"
*ptr=addr;  //obviously not

Such that this will now be the actual address of the pointer and usuable that way normally (if you need to know why, see
http://cboard.cprogramming.com/showthread.php?t=107115

convert it to unsigned long using strtoul
then, cast to pointer of the appropriate type

Originally Posted by vart

convert it to unsigned long using strtoul
then, cast to pointer of the appropriate type

I presume that's what you were trying to do with your example in the other thread, but it doesn't work!

Originally Posted by MK27

I presume that's what you were trying to do with your example in the other thread, but it doesn't work!

Works for me

Code:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
	char sAddr[] = "0x00ac0098";
	unsigned int uAddr = strtoul(sAddr,NULL,0);
	void* pAddr = (void*) uAddr;

	printf("&#37;p", pAddr);
	return 0;
}

it prints exactly the same address I have put into the string, of course dereferencing this address will fail - because it is just some random value - low chance to have something available there - put the address of something accessable - and you will have no problem dereferencing it...

Originally Posted by vart

Works for me

Well, it is also somewhat different than your other code -- but thanks thanks thanks vart, that will do my just fine