Thread: Help Please.

hello,

Here's the deal, i am writing a cprogram for the first time and i have to convert numbers into words. Sucah as a check has the amount written in numbers and then the words. i have been looking for the proper coding for about 1.5 weeks and i am still stuck. any suggestions will be helpful I was told this was a simple function to do but for the life of me i can't figure it out so if someone could point me in the right direction i woulkd appreciate it..

Thanks
Frustraded student...=(

2 into Two is what i am looking to do..

as for looking up the itoa function i have no listing of that in my book.. is it a function in C ??

Thanks

Hi Krullt!

So how far DID you get... Could you post some code? Maybe you can start with something like this.

Code:

#include <stdio.h>
char dec1[10]={"Zero", "One", ...}; 
main()
{
   int val;
   scanf("%i", &val);

   if(val>=0 && val<10)
      printf("%i %s\n", val, dec1[val]);
   else
      printf("Can't count to ten yet...\n");
}

Hope this helps...
alex

ok here is what i have written.. the problem i am having is i don't know how to take my calculation and convert the answer in to words.

IE

$320 to three hundred and twenty


#include <stdio.h>

int main(void)
{
/*THIS PROGRAM IS DESIGNED TO PRINT OUT A CHECK*/

printf("****************************************** **********\n");
printf("* Acme Computer Company *\n");
printf("* 2345 First Street *\n");
printf("* Los Angeles, CA 10101-0001 *\n");
printf("* *\n");
printf("* *\n");
printf("* *\n");
printf("* William H. Taylor ");
Money (); /*CALCULATION OF AMOUNT TO BE PAYED*/
printf("* *\n");
printf("* *\n");
printf("* *\n");
printf("* John. Q Smith *\n");
printf("* *\n");
printf("* :987654321|: 1236547896542||*58749 *\n");
/*ACCOUNT NUMBER*/
printf("****************************************** **********\n");
return 0;
}

void Money ()
{
/*BASIC CALCULATION TO COME UP WITH THE AMOUNT TO BE PAYED*/
float fica, insurance, gross, net;

gross = 500;
fica = 500 * .075;
insurance = 500 * .01;
net = gross - (fica + insurance);
printf(" $%.2f *\n", net);
}

Originally posted by Krullt
ok here is what i have written.. the problem i am having is i don't know how to take my calculation and convert the answer in to words.

IE

$320 to three hundred and twenty

printf(" $%.2f *\n", net);

You could use code like this:

Code:

int cents, dollar100, dollar10, dollar...
...
cents=100*net; /* compute the number of dollarcents */
dollar100=cents/10000; /* compute the "3" in your example */
cents-=dollar100*10000;
dollar10=cents/1000; /* the "2" */
cents-=dollar10*1000;
dollars=cents/100; /* the "0" */
cents-=dollars*100;
cent10=cents/10; /* first decimal after . */
cents-=cent10*10; /* and finally the second decimal after . */

An easier way (probably what a more experienced C programmer would use) is by using the function sprintf. It does the same job as printf, but puts the formatted output into a string and not onto the screen.

Code:

char netstr[9];
...
sprintf(valstr, "%08.2f", net);
/* printf("%s\n", netstr); */
/* printf("%i%i%i dollars", netstr[2]-'0', netstr[3]-'0', netstr[4]-'0');
printf(" and %i%i cents\n", netstr[6]-'0' netstr[7]-'0');

I think this gives all the pieces of math you need to convert the value into english words...

Hope this helps...
alex