Thread: Hamming Distance?

  1. #1
    Registered User
    Join Date
    Jul 2008

    Hamming Distance?

    ive dynamically allocated an array of two bytes using:
    char *ptr = (char *)malloc (2*sizeof(char));

    how can I find the Hamming distance between the two bytes?

  2. #2
    The larch
    Join Date
    May 2006
    Do you mean this?

    I don't see how the allocation of two bytes has anything to do with it...
    I might be wrong.

    Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
    Quoted more than 1000 times (I hope).

  3. #3
    Registered User
    Join Date
    Jul 2008
    the example section of that page says:

    The Hamming distance between:

    10 *1* 1 *1* 01 and 10 *0* 1 *0* 01 is 2.

    im trying to find the Hamming Distance between the two bytes in the memory allocated.

  4. #4
    The superhaterodyne twomers's Avatar
    Join Date
    Dec 2005
    I'd say you should xor them together, and count the number of 1's from the return of the xoring. To count the number of 1s one solution might be something like... Change this to work for your own situation (note I haven't tested this)

    int c, xor_res = thinga^thingb;
    int hamm_dist;
    for( c=1; c; c<<=1 )
      hamm_dist += (xor_res & c );
    printf( "Hamming distance between &#37;d and %d, is %d\n", thinga, thingb, hamm_dist );
    Or see the wiki link code. Prolly better and more thought out.

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