char type and bits

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Originally Posted by QuantumPete

I should have said "treat these" instead of "decodes these". Sorry about the confusion!

QuantumPete

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But it doesn't. The implisit conversion will sign extend the char to an int when char is passed as a single arguement.

String and character literal escapes must be spesified as unsigned octal or hex, but that has nothing to do with printf.

Printing functions don't care about the sign of a character, because they just map each set of eight bits to a symbol. Signed or unsigned these bits still have the same mapping.

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Originally Posted by King Mir

But it doesn't. The implisit conversion will sign extend the char to an int when char is passed as a single arguement.

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But then the corresponding %c argument is converted to unsigned char after being converted to int.

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Originally Posted by C89 draft 4.9.6.1

c The int argument is converted to an unsigned char , and the resulting character is written.

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Hm. Well if the standard says that then I guess it's true. But its odd that they specify that considering that it makes no difference what so ever, except perhaps that code pages are commonly listed as unsigned values.