Thread: how can i access a direct (absolute, not the offset) memory address?

how can i access a direct (absolute, not the offset) memory
address?

here is what i tried:
wrote a program that ask's for an address from the user,
creates a FAR pointer to that adress and shows it. then the
user can increment/decrement the value in that address by
pressing p(inc+) and m(dec-).

NOW, i compiled that program and opened it twice (in 2
different windows) and gave twice the same address to it.
now look what happen - if i change the value in
one "window" of the program, it DOES NOT change in the
other! even if they point to the same address in the memory!

here is the code snippet:

Code:

//------------------------------------------------------

#include <stdio.h>        //INCLUDE EVERY KNOWN HEADER FILE
#include <conio.h>        //FOR ANY CASE...
#include <iostream.h>
#include <dos.h>
#include <process.h>


main()
{
 int far *ptr;         //FAR POINTER!!!
 long address;         
 char key=0;     //A KEY FROM THE KEYBOARD
 int temp=0;

 clrscr();

 cout<<"Enter Address:";
 cin>>hex>>address;           //GETS THE ADDRESS
 clrscr();

 (long)ptr=address; temp=*ptr; //PUTS THE ADDRESS IN THE PTR

 cout<<"["<<hex<<(unsigned long)ptr<<"]="<<*ptr<<"  =  "<<
(char)(*ptr);    

//SHOWS: [address]=value=ASCII symbol.
     

 while (key!=27)   //WHILE YOU DONT PRESS ESC.
 {
  while(!kbhit())  //WHILE KEY IS NOT PRESSED
  {
   if (temp!=*ptr) { temp=*ptr; clrscr();  cout<<"["<<hex<<
   (unsigned long)ptr<<"]="<<*ptr<<"  =  "<<(char)(*ptr); };
       
   //IF THE VALUE HAS CHANGED, CLEAR THE SCREEN AND SHOW 
   //AGAIN

   if (key=='p') {key=0; (*ptr)++; }   //INCREMENT VALUE
   if (key=='m') {key=0; (*ptr)--;       } //DEC. VALUE
  };
  key=getch(); //IF A KEY IS PRESSED, READ IT FROM THE 
               //KEYBOARD
 };
 return 0;  //IF ESC WAS THE KEY, EXIT THE PROGRAM
}
//---------------------------------------------------------