Yes, it did compile when I got all the syntax right, but it gave me warnings about the array initialization. I put the internal braces betrween the array elements and now I have no warnings or errors.
There is another problem. I get a data abort message when the programs runs. I may have some illegal math operation. I have to look into that before I can ask for help.
Thanks for your help.
I got rid of the data abort message, it was due to a while(1) being cleared. It is valid in the actual code, but not for my testing.
My original example was simplified. My actual program statements are more complex, and I am having a difficult time with Braces in:
Code:int x; int y; const int p[4][2] = {(1,2), (3,4), (5,6), (7,8)}; if (x >= p[0][0]) (y=p[0][1]); else {if (x>=p[1][0]) (y=(p[1][1] * (1+(x/(p[1][0]-p[0][0]))))); else {if (x>=p[2][0]) (y=(p[2][1] * (1+(x/(p[2][0]-p[1][0]))))); else {if (x>=p[3][0]) (y=(p[3][1] * (1+(x/(p[3][0]-p[2][0]))))); else {if (x>=p[4][0]) (y=(p[4][1] * (1+(x/(p[4][0]-p[3][0]))))); else (x = 154);}}}}
Last edited by danlee58; 08-30-2008 at 07:42 AM.
It's really easy.Originally Posted by danlee58
Every IF begins with { and ends with }.Code:int x; int y; const int p[4][2] = { {1, 2}, {3, 4}, {5, 6}, {7, 8} }; if (x >= p[0][0]) y=p[0][1]; else { if (x >= p[1][0]) { y = ( p[1][1] * ( 1 + ( x / (p[1][0] - p[0][0]) ) ) ); } else { if (x >= p[2][0]) { y = ( p[2][1] * ( 1 + ( x / (p[2][0] - p[1][0]) ) ) ); } else { if (x >= p[3][0]) { y = ( p[3][1] * ( 1 + ( x / (p[3][0] - p[2][0]) ) ) ); } else { if (x >= p[4][0]) { y = ( p[4][1] * ( 1 + ( x / (p[4][0] - p[3][0]) ) ) ); } else x = 154; } } } }
Every line must be terminated with ;. Use more whitespace to make it more visible.
This may seem like a huge amount of whitespace, but it's necessary to make your convulted ifs readable.
Elysia,
Thanks for the help. That worked. Part of my difficulty is that I have a hard time telling the difference between a Brace and a Parenthesis.
I had some other problems in the code, but I was able to fix them. I had to declare the const array a floating point, since the results of a calculation is fractional, and would return zero and have no effect if left as an integer.
Now that section of code is working, I will go on to the next, but much of what I have to do is similar to this section, but with larger arrays and with more dimensions.
Wilst most of the time a line and a statement is the same thing, it is not a line that must end with a ; - a statment ends with ;
There are several examples in the posted code where the same statement covers more than one line - if-statements are commonly written over two or more lines, where the first line is the if (condition), and the second line contains the "then do" part of the if-statement. Note that an "else" is a separate statement [but it must follow immediately after the if-"then-do" block.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
