Array of Constants Initialization

Yes, it did compile when I got all the syntax right, but it gave me warnings about the array initialization. I put the internal braces betrween the array elements and now I have no warnings or errors.

There is another problem. I get a data abort message when the programs runs. I may have some illegal math operation. I have to look into that before I can ask for help.

Thanks for your help.

I got rid of the data abort message, it was due to a while(1) being cleared. It is valid in the actual code, but not for my testing.

My original example was simplified. My actual program statements are more complex, and I am having a difficult time with Braces in:

Code:

---

int x;
int y;
const int p[4][2] = {(1,2), (3,4), (5,6), (7,8)};
if (x >= p[0][0]) (y=p[0][1]);
else {if (x>=p[1][0]) (y=(p[1][1] * (1+(x/(p[1][0]-p[0][0])))));
        else {if (x>=p[2][0]) (y=(p[2][1] * (1+(x/(p[2][0]-p[1][0])))));
                    else {if (x>=p[3][0]) (y=(p[3][1] * (1+(x/(p[3][0]-p[2][0])))));
                              else {if (x>=p[4][0]) (y=(p[4][1] * (1+(x/(p[4][0]-p[3][0])))));
                                      else (x = 154);}}}}

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Quote:

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Originally Posted by danlee58

I got rid of the data abort message, it was due to a while(1) being cleared. It is valid in the actual code, but not for my testing.

My original example was simplified. My actual program statements are more complex, and I am having a difficult time with Braces in:

Code:

---

int x;
int y;
const int p[4][2] = {(1,2), (3,4), (5,6), (7,8)};
if (x >= p[0][0]) (y=p[0][1]);
else {if (x>=p[1][0]) (y=(p[1][1] * (1+(x/(p[1][0]-p[0][0])))));
        else {if (x>=p[2][0]) (y=(p[2][1] * (1+(x/(p[2][0]-p[1][0])))));
                    else {if (x>=p[3][0]) (y=(p[3][1] * (1+(x/(p[3][0]-p[2][0])))));
                              else {if (x>=p[4][0]) (y=(p[4][1] * (1+(x/(p[4][0]-p[3][0])))));
                                      else (x = 154)}}}};

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It's really easy.

Code:

---

int x;
int y;
const int p[4][2] = { {1, 2}, {3, 4}, {5, 6}, {7, 8} };
if (x >= p[0][0])
    y=p[0][1];
else
{
    if (x >= p[1][0])
    {
        y = (
            p[1][1] *
            (
                1 + ( x / (p[1][0] - p[0][0]) )
            ) );
    }
    else
    {
        if (x >= p[2][0])
        {
            y = (
                p[2][1] *
                (
                    1 + ( x / (p[2][0] - p[1][0]) )
                ) );
        }
        else
        {
            if (x >= p[3][0])
            {
                y = (
                    p[3][1] *
                    (
                        1 + ( x / (p[3][0] - p[2][0]) )
                    ) );
            }
            else
            {
                if (x >= p[4][0])
                {
                    y = (
                        p[4][1] *
                        (
                            1 + ( x / (p[4][0] - p[3][0]) )
                        ) );
                }
                else
                    x = 154;
            }
        }
    }
}

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Every IF begins with { and ends with }.
Every line must be terminated with ;. Use more whitespace to make it more visible.
This may seem like a huge amount of whitespace, but it's necessary to make your convulted ifs readable.

Elysia,

Thanks for the help. That worked. Part of my difficulty is that I have a hard time telling the difference between a Brace and a Parenthesis.

I had some other problems in the code, but I was able to fix them. I had to declare the const array a floating point, since the results of a calculation is fractional, and would return zero and have no effect if left as an integer.

Now that section of code is working, I will go on to the next, but much of what I have to do is similar to this section, but with larger arrays and with more dimensions.

Quote:

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Originally Posted by Elysia

Every line must be terminated with ;

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Wilst most of the time a line and a statement is the same thing, it is not a line that must end with a ; - a statment ends with ;

There are several examples in the posted code where the same statement covers more than one line - if-statements are commonly written over two or more lines, where the first line is the if (condition), and the second line contains the "then do" part of the if-statement. Note that an "else" is a separate statement [but it must follow immediately after the if-"then-do" block.

--
Mats