Thread: Why does this code give two different memory addresses?

I was just looking at this code and I can't explain why it's working in this way. I would expect the value given by &x and ptr to be the same, but it doesn't if you compile and run the program.

Code:

int main(int argc, char *argv[])
{
       int x=5, *ptr;           // x set to 5 for example only

       *ptr = x;

       printf("%x\n%x\n\n, ptr, &x);
       free(ptr);

       return 0;
}

I can't understand why they give different addresses, but for some reason, they do. I would be grateful if someone could explain to me why this is the case.