Thread: Help! confused on how to run this program about money

this is sort of like an atm-ish project....
i thought of many possible things i learn't but maybe it still isn't enough...
maybe you can help me finish this program with just basic variables in it.. printf, scanf, and the like...

THE PROBLEM: create a program that will ask an amount in pesos(integer) and determine the lowest # of bills he will need to achieve the amount entered. The bills in use are 1000peso, 500peso, 200peso, 100peso, 50peso, 20peso, 10peso, 5peso, 1peso.
/* peso is a currency XD */

an example would be if i entered an amount of 1898 pesos, it would come up with

you need:
peso1000:1
peso500:1
peso200:1
peso100:1
oeso50:1
peso20:2
peso10:
peso5:1
peso1:3

so far i've made this: i know the nAmnt's in the printf's are wrong but i just don't know what to put.

Code:

#include <stdio.h>
main()
{
	int nPeso1000,
	    nPeso500,
	    nPeso200,
	    nPeso100,
	    nPeso50,
	    nPeso20,
	    nCoin10,
	    nCoin5,
	    nCoin1,
	    n,
	    nAmnt;

	    printf("Enter Amount:");
	    scanf("&#37;d", nAmnt);
	    printf("xxxxxxxxx\n");
	    printf("xxBillsxx\n");
	    printf("xxxxxxxxx\n\n");
	    printf("1000:%d\n",nAmnt);
	    printf("500:%d\n", nAmnt);
	    printf("500:%d\n", nAmnt);
	    printf("200:%d\n", nAmnt);
	    printf("100:%d\n", nAmnt);
	    printf("50:%d\n", nAmnt);
	    printf("20:%d\n\n", nAmnt);
	    printf("xxxxxxxxx\n");
	    printf("xxCoinsxx\n");
	    printf("xxxxxxxxx\n\n");
	    printf("10:%d\n", nAmnt);
	    printf("5:%d\n", nAmnt);
	    printf("1:%d\n", nAmnt);
	    getch();
	    return 0;
 }

1898 / 1000 = 1 <-- this is your first answer
1898 &#37; 1000 = 898 <-- use this as the start for your next answer

Do that all the way down through your currency values.