Passing function as argument

Quote:

---

Originally Posted by Elysia

How do you do it? Passing is easy:
func(&function);

Declaring a function to take a pointer to a function is less trivial, but something along the lines of:
typedef return_type (name)(argument_type argument_name);
void foo(name* pFunction);

---

Does that work? I usually see this instead:

typedef return_type (*name)(argument_type argument_name);
void foo(name pFunction);

Yes, both work, but I tend to use the former because it more visible that it is actually a pointer.