Thread: Another problem with a program

I'm trying to make a program that will take a number grade and turn it into a letter grade. As I said in another post, this is my first day programming. Here is my program:

Code:

#include<stdio.h>
#pragma warning(disable:4996)

int getNumGrade ();
int calcLetterGrade();
int outputToScreen (int, int);

int main (void)
{
int numgrade = 0;
int lettergrade = 0;
char cgoAgain = 'y';
printf ("Enter numerical grade value now:");
numgrade = getNumGrade ();
lettergrade = calcLetterGrade();
int ouputToScreen (numgrade, lettergrade);

while (cgoAgain =='y' || cgoAgain == 'Y');
{
printf("\nEnter numerical grade value now:");
numgrade = getNumGrade(numgrade);

return 0;
}

int getNumGrade()
{
int numgrade = 0;
scanf("%d%*c",&numgrade);
return numgrade;
}

int calcLetterGrade (numgrade)
{
	int lettergrade;
	if (numgrade < 60)
		lettergrade = 'F';
	if (numgrade <70)
		lettergrade = 'D';
	if(numgrade < 80)
		lettergrade = 'C';
	if (numgrade <90)
		lettergrade = 'B';
	if (numgrade <100)
		lettergrade = 'A';
	return lettergrade;
}

int outputToScreen (int numgrade, int lettergrade)
{
	printf ("\n When Numerical grade is %d, letter grade is %d", numgrade, lettergrade);
}

I get the following error:


(16) : error C2143: syntax error : missing ';' before 'type'
(26) : error C2143: syntax error : missing ';' before 'type'

How can I fix those?

Thank you, I corrected that one. Where does the line 16 error come from, though?

Could I make else if statements?

I tried that earlier, but it said they were illegal else statements.

I thought I defined outputToScreen earlier in the prototype? Should it be

outputToScreen (numgrade, lettergrade);

in the prototype?

Is this any better or am I taking steps backward? I'll bold the changes.

Code:

#include<stdio.h>
#pragma warning(disable:4996)

int getNumGrade ();
int calcLetterGrade();
int outputToScreen (int, int);

int main (void)
{
int numgrade = 0;
int lettergrade = 0;
char cgoAgain = 'y';
printf ("Enter numerical grade value now:");
numgrade = getNumGrade ();
lettergrade = calcLetterGrade();
ouputToScreen (numgrade, lettergrade);
printf ("\nWould you like to enter another grade? ");

while (cgoAgain =='y' || cgoAgain == 'Y')
{
printf("\nEnter numerical grade value now:");
numgrade = getNumGrade(numgrade);
}
return 0;
}

int getNumGrade()
{
int numgrade = 0;
scanf("&#37;d%*c",&numgrade);
return numgrade;
}

int calcLetterGrade (numgrade)
{
	int lettergrade;
	if (numgrade < 60)
		lettergrade = 'F';
	if (numgrade <70)
		lettergrade = 'D';
	if(numgrade < 80)
		lettergrade = 'C';
	if (numgrade <90)
		lettergrade = 'B';
	if (numgrade <100)
		lettergrade = 'A';
	return lettergrade;
}

int outputToScreen (int numgrade, int lettergrade)
{
	printf ("\n When Numerical grade is %d, letter grade is %d", numgrade, lettergrade);
	return 0;
}

That is to attempt to fix the line 16 error, this is the new error code I get.

1>(16) : warning C4013: 'ouputToScreen' undefined; assuming extern returning int
1>Linking...
1>Lab2a.obj : error LNK2019: unresolved external symbol _ouputToScreen referenced in function _main

1>(16) : warning C4013: 'ouputToScreen' undefined; assuming extern returning int
1>Linking...
1>Lab2a.obj : error LNK2019: unresolved external symbol _ouputToScreen referenced in function _main

How do I fix this one? I'll make the else statements and see if they work.

Here's the code with the else statements, no errors on those:

Code:

#include<stdio.h>
#pragma warning(disable:4996)

int getNumGrade ();
int calcLetterGrade();
int outputToScreen (int, int);

int main (void)
{
int numgrade = 0;
int lettergrade = 0;
char cgoAgain = 'y';
printf ("Enter numerical grade value now:");
numgrade = getNumGrade ();
lettergrade = calcLetterGrade();
ouputToScreen (numgrade, lettergrade);
printf ("Would you like to enter another grade?");

while (cgoAgain =='y' || cgoAgain == 'Y')
{
printf("\nEnter numerical grade value now:");
numgrade = getNumGrade(numgrade);
}
return 0;
}

int getNumGrade()
{
int numgrade = 0;
scanf("&#37;d%*c",&numgrade);
return numgrade;
}

int calcLetterGrade (numgrade)
{
	int lettergrade;
	if (numgrade < 60)
		lettergrade = 'F';
	else if (numgrade <70)
		lettergrade = 'D';
	else if(numgrade < 80)
		lettergrade = 'C';
	else if (numgrade <90)
		lettergrade = 'B';
	else if (numgrade <100)
		lettergrade = 'A';
	return lettergrade;
}

int outputToScreen (int numgrade, int lettergrade)
{
	printf ("\n When Numerical grade is %d, letter grade is %d", numgrade, lettergrade);
	return 0;
}

Here's the error again:

(16) : warning C4013: 'ouputToScreen' undefined; assuming extern returning int
1>Linking...
1>Lab2a.obj : error LNK2019: unresolved external symbol _ouputToScreen referenced in function _main

In the outputToScreen function, I'm wanting the program to write that information on screen. I'm not sure I understand where the information should be returned, if it should be returned at all.

As far as the prototype goes, I'm wanting to declare the prototype. Is that the wrong way to do it?

It is saying outputToScreen must return a value, but where should it be returned, I'm totally confused on that.