Thread: printf() vs puts() behavior

When I do the following

m-net% more mod.c

Code:

#include <stdio.h>

int main (void)
{
   char str[] = "Aamit";
   *str='R';
   puts(str);
   return 0;
}

The output is fine.

Code:

m-net% gcc -g -Wall mod.c -o mod
m-net% ./mod
Ramit

However, when I replace puts() with printf()

m-net%m-net% more mod.c

Code:

#include <stdio.h>

int main (void)
{
   char str[] = "Aamit";
   *str='R';
   printf("%s \n " ,str);
   return 0;
}

I get some junk afterwards.

Code:

m-net% gcc -g -Wall mod.c -o mod
m-net% ./mod
Ramit
 %                                                                              
m-net%

Whis is this?

Code:

>   printf("%s \n " ,str);

Try removing the space after the newline in the above printf(), and see if you still have the problem.

Originally Posted by gwarf420

printf prints all the characters in an array until it reaches the \0 character. You need to null out the rest of the characters in the array if you do not want them to print.

The string is already null terminated... The *str line doesn't change that.

> Then how comes this doesn't happen with puts()?
Because puts() puts a new line on the end for you...

Swoopy has already answered your question IMO.