Ew, count with integral types, not doubles.
ie,
> ? (obviously with correct notation)Code:int i = 0;
double x = 0.0;
for(i = 0; i < 10; i++)
{
x = (double) (i + 1);
/* ... */
}
Yes
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Ew, count with integral types, not doubles.
ie,
> ? (obviously with correct notation)Code:int i = 0;
double x = 0.0;
for(i = 0; i < 10; i++)
{
x = (double) (i + 1);
/* ... */
}
Yes