Compiler translation and division remainders

[CodeGeek20]

I have two questions. One, the odds of me getting my hands on source code that I actually care about that was written in Code::Blocks are two small to calculate. Such the case, I cannot open a source file, hit F9, and go. Is there an efficient way of translating other people's source code into your compiler so you can compile it raw?

Two, I have read the method for converting a number to binary is the number divided by two, the remainder (one or zero) becomes a binary digit, and the result is divided by two. This process continues until the result is zero or < 0. The remainders are then constructed in reverse order to form a set of 0's and 1's that represents the number. I tried to write a program to convert a number into binary, but what I don't know is, how do I take a division, but the remainder in one int array, and the result in an int variable to be re-divided?

Thanks,
-CG20

[mike_g]

Modulo 2 will get you the remainder. IE: 5 % 2 would equal 1 then put it in your array something like:

for(i=0; i<32; i++)
{
    array[i] = num % 2;
    num /=2;
}

[tabstop]

It's not quite clear from your question: are you using C::B or are they? I'm guessing that since you're saying "F9", you're the one using C::B. In that case, you really should be able to hit F9 and go -- I can, anyway. You'll have to provide more information about what's going wrong.

[CodeGeek20]

I am using C::B. But that's not really important. I may not have all the stuff I need or something.

mike_g, I don't understand that code. What is that % operator doing? I need to divide a number, and put the remainder in one array, and put the result in another.

-CG20

[tabstop]

As mentioned, % gives the remainder. / does division.