Hello,
I am return a string from a function. Function prototype:
Code:char* ToUpper(char *str, const int length);
In my main i have the following:
I keep on getting the following error message.Code:char string2[] = "Hello how are you today?"; strcpy(string2, ToUpper(string2, strlen(string2));
error C2143: syntax error : missing ')' before ';'
Any advice would be most gratefull,
Thanks,
Count your parentheses. You have 3 opening but only 2 closing on that line.Originally Posted by steve1_rm
abachler: "A great programmer never stops optimizing a piece of code until it consists of nothing but preprocessor directives and comments"
Thanks,
I was looking everywhere.
A stupid mistake. I will have to look more closely next time.
Try putting spaces at certain places to make it easier to spot where there needs to be ending ).
> strcpy(string2, ToUpper(string2, strlen(string2));
If ToUpper() returns string2, then not only is the strcpy a waste of time, it's also undefined.
Very few C library functions which move data around are guaranteed to do the "right thing" when the source and destination overlap. memmove() is an exception.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
