receiving function value which returns array of strings

**saeed144** · 04-27-2008

Dear helper,

How can I print the value this function returns?
const char** available_locations (void)

This function is to query the available/support printer locations of the Server. This table is an array of strings where each string represents the printer location of supported printer. The last entry of the list is a NULL pointer.

Please tell me how to define the variable that gets the returned value, and how to print such variable,

Thanks in advance,
Saeed144

**laserlight** · 04-27-2008

Just call the function:

Code:

const char** locations = available_locations();

Now, *locations gives you the first location, which you can print and compare to NULL. ++locations causes locations to point to the next location. With that you should be able to construct a loop to print the available locations.

**saeed144** · 04-27-2008

Thanks, it worked,
Yet about the printing it,

if (!*locations) printf ("%s", locations[0]);

Is it right? I just want to print the first Location string,

Thanks again,
Saeed144

**laserlight** · 04-27-2008

More like:

Code:

if (*locations) printf("&#37;s", locations[0]);

Or to be consistent:

Code:

if (locations[0]) printf("%s", locations[0]);

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