combining boolean conditions with parenthesis

[mc61]

Hello,

I was wondering whether the expected parenthesis hierarchy is respected when combining boolean conditions in a do-while loop.

To be concrete, consider this:

do
{
...
}
while ( A && ( B || C || D ) )

Then, the loop terminates when either A is false or (B||C||D) is false, and for this last one to be false, then B and C and D have to be false.

Am I right? If so, this works in both C and C++?

Thanks for your help,

mc61




Thanks for your help,

mc61

[matsp]

It terminates if either A is false on it's own or B, C and D are all false.

Note that A is tested first, and if it's FALSE, no other test has to be performed, and you can rely on this in the compiler (for example you can do

if (p != NULL && *p != 7)  ...

and you can be sure that *p is never being accessed if p is NULL.

And yes, it's the same in C and C++.

--
Mats

[mc61]

Thanks matsp!

mc61