Thread: calling a char *function

I have a function, char *move(Head head);

It has already been declared and the function is created.

However, when I try calling it from main like:

move(head);

It says implicit declaration.

If I try:

*move(head); - it gives me an error, likewise for &move(head) - how do I call this type of function?

Have you prototyped it?

As in, at that point in the program is it declared?

Yes, it's declared in a header file, it's not the only function declared in a header file, so I don't get why it's causing problems.

Code posty time

Hmm I can't post the code unfortunately, it's an assignment =( . I don't want someone copying the code (just incase someone from my class is in here) and then they copy something from me and then when they do a plagiarism test, I may get busted.

But it looks something like this:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct buffer *EX;
struct buffer {
  char *buffer;
  EX next;
};

EX makeNode (void);
char *move (EX ex);

int main (void) {
  char str[] = "hi, \nmy name is Jude\n";
  int t_len;

  t_len = strlen(str);

   //do stuff with strings

  move(ex);

  return  0;
}

//other functions

char *move (Ex ex) {
  char *buf;
  //stuff

  return (buf);

  } 


EX makeNode(void){

  EX node;
  node = (EX)malloc(sizeof(*node));

  return (node);
}

Code:

char *move (Ex ex) {
  char *buf;
  //stuff

  return (buf);

  }

That should be

Code:

char * move(EX ex)

also, you don't declare the 'ex' you are passing to move in main()

Originally Posted by rags_to_riches

Spot the difference:

Code:

char *move (EX ex);
char *move (Ex ex)

Sorry, that wasn't there in the original code, that was just a typo as I was typing it out here.

Nvm, I found out what was wrong.

The original was actually dumpTB

and I had called it dump, missing the TB, that's why it was implicit. Damn silly mistakes.

Sorry all

Seriously, I'd avoid 'masking' pointers... unless your assignment says you have to. Kinda hard to follow IMO.