Thread: finally my salary program but...........

#include <stdio.h>

int main()
{
float salary;
int rate, hours;
rate = 0;
hours = 0;


printf( "Enter # of hours worked (-1 to end): " );
scanf( "%d", &hours );


while ( hours != -1 ){
printf( "Enter hourly rate of the worker ($00.00): " );
scanf( "%d", &rate );

if ( hours <= 40 )
salary = hours * rate;

if ( hours > 40 )
salary = ( float ) (hours - 40) * (1.50 * rate) + (40 * rate);

printf( "Salary is $%.2f\n\n\n", salary );

printf( "Enter # of hours worked (-1 to end): " );
scanf( "%d", &hours );
}


return 0;
}



Almost done guys!!! i just want to know how to input decimal values like 9.56 in the rate field without causing a infinite loop...thaaaaanks!

like this??????

#include <stdio.h>

int main()
{
float salary;
float rate;
int hours;
rate = 0;
hours = 0;


printf( "Enter # of hours worked (-1 to end): " );
scanf( "%d", &hours );


while ( hours != -1 ){
printf( "Enter hourly rate of the worker ($00.00): " );
scanf( "%.2f", &rate );
.............

if not how?
plz help me because im almost sleeping after 5 hours trying to figure out this one...thanks

thanks for the cleaning code buuuut we are not supposed to know that yet. its an assignment and if I put that, the teacher will think that I stole the code or sumthing like that.

heelp me plzzz....compiles but doesnt work...

thanks man....u better go to sleep....i will do it and try it tomorrow...can not think right know


thanks again

Here dude, it's 1.5 * salary, not 3/2 because 3/2=1.
Also if you want -1 to exit program right away,
it has to be the last statement in your while loop,
but you also need it before the loop too, for the first time through.
Here you go:

#include <stdio.h>

int main()
{
float salary;
int rate, hours;

printf( "Enter # of hours worked (-1 to end): " );
scanf( "%d", &hours );

while ( hours != -1 ){

printf( "Enter hourly rate of the worker ($00.00): " );
scanf( "%d", &rate );

if ( hours <= 40 )
salary = hours * rate;

else
salary = ( float ) (hours - 40) * (1.5 * rate) + (40 * rate);

printf( "Salary is %.2f\n\n\n", salary );

printf( "Enter # of hours worked (-1 to end): " );
scanf( "%d", &hours );

}


return 0;
}

1.5 * rate I mean. look at the code