Thread: Passing arg 1 of `atoi' makes pointer from integer without a cast, Please help.

Code:

char c,tmp[3],camadas_dados[5000],*ptr;
int camada_actual,area_camada,boxes_camada,wires_camada,temp,layers,boxes,wires,bk;

    void dadosCamada () {
         int s; //0 = area_camada, 1 = boxes_camada, 2 = wires_camada
         bk=pX;
         area_camada = boxes_camada = wires_camada = 0;
         
         while(camadas_dados[bk] != ']') {
          if(isdigit(camadas_dados[bk])) {
           area_camada = (s == 0) ? area_camada*10 + atoi(camadas_dados[bk]) : area_camada;
           boxes_camada = (s == 1) ? boxes_camada*10 + atoi(camadas_dados[bk]) : boxes_camada;
           wires_camada = (s == 2) ? wires_camada*10 + atoi(camadas_dados[bk]) : wires_camada;
          }
          else if(s!=0){s++;}
          bk++;
         }
         }

I'm getting the error here:

PHP Code:

           area_camada = (s == 0) ? area_camada*10 + atoi(camadas_dados[bk]) : area_camada;
           boxes_camada = (s == 1) ? boxes_camada*10 + atoi(camadas_dados[bk]) : boxes_camada;
           wires_camada = (s == 2) ? wires_camada*10 + atoi(camadas_dados[bk]) : wires_camada; 


[Warning] passing arg 1 of `atoi' makes pointer from integer without a cast
[Warning] passing arg 1 of `atoi' makes pointer from integer without a cast
[Warning] passing arg 1 of `atoi' makes pointer from integer without a cast

This error may be very stupid but i can't find it.. Thanks for helping

I edited the post to add the line:

char c,tmp[3],camadas_dados[5000],*ptr;

Originally Posted by NeonBlack

atoi() as the name suggests, takes an array and returns and integer. You're giving it a char.
try

Code:

atoi(camadas_dados)

Omg you're right! Stupid me.

can i make atoi(camadas_dados+bk) ? because camadas_dados will start from [0], i want it to start from [bk].

Thanks!

Okay, thank you