1. ## Simple program help

Ok this shouldn't take too long to fix, simple program for working out resistance and voltage for some amplifier...

Code:
```#include <stdio.h>

#define Vc (5.5);

#define Ve (1.1);

#define Vin (0.075);       /* Voltages */

#define Hfe (100);

int main(void)
{
float Vout, R1, R2, R3, R4;
float Ic, Vcc;
float Ib, Vb, Ks;

/* Enter the current, from 2e-3 to 5e-3 */
printf("Enter Ic: ");
scanf("%f", &Ic);

/* Enter the voltage, 9.0, 10.0 or 12.0 */
printf("Enter Vcc: ");
scanf("%f", &Vcc);

Ib = Ic / Hfe;
R1 = (Vcc - Vc) / (Ic);
R2 = (Ve / Ic + Ib) ;
Vb = 0.7 + Ve;
R3 = (Vcc - Vb)/ (6 * Ib);
R4 = Vb	/ (5 * Ib);
Ks= R1/R2;
Vout = Ks * Vin;

printf("**********************\n");
printf("R1= %6.0f Ohms \n", R1);
printf("R2= %6.0f Ohms \n", R2);
printf("R3= %6.0f Ohms \n", R3);
printf("R4= %6.0f Ohms \n", R4);
printf("Vout= %3.1f  V \n", Vout);

return(0);
}```

Ok, the green lines are the ones I'm having trouble with, the compiler says "error: expected ')' before ';' token" for both the lines
And also for the red lines, if I swap them around like so
Code:
```Vb = Ve + 0.7
Vout = Vin * Ks```
The compiler says "Warning: statement with no effect" and "error: invalid type of 'unary *' " respectively. But if I have them the way I do as above, it works fine.

2. #defines and semicolons; don't mix.

3. haha, wow, I can't believe I missed that. I don't even know why I put them in there
Thanks for the help

4. Also, it's good to have everything for the pre-processor in caps -- it makes it easier to read.

For example, I'd think 'Vin' is a variable name at first glance. Constants rather than defines would do well here.