Thread: Simple program help

Ok this shouldn't take too long to fix, simple program for working out resistance and voltage for some amplifier...

Code:

#include <stdio.h>


#define Vc (5.5);

#define Ve (1.1);

#define Vin (0.075);       /* Voltages */

#define Hfe (100);

int main(void)
{
	float Vout, R1, R2, R3, R4;
	float Ic, Vcc;
	float Ib, Vb, Ks;
	
	/* Enter the current, from 2e-3 to 5e-3 */
	printf("Enter Ic: ");
	scanf("%f", &Ic);
	
        /* Enter the voltage, 9.0, 10.0 or 12.0 */
	printf("Enter Vcc: ");
	scanf("%f", &Vcc);
	
        Ib = Ic / Hfe;
	R1 = (Vcc - Vc) / (Ic);
	R2 = (Ve / Ic + Ib) ;
	Vb = 0.7 + Ve;
	R3 = (Vcc - Vb)/ (6 * Ib);
	R4 = Vb	/ (5 * Ib);	   
	Ks= R1/R2; 
	Vout = Ks * Vin;
	
	printf("**********************\n");
	printf("R1= %6.0f Ohms \n", R1);
	printf("R2= %6.0f Ohms \n", R2);
	printf("R3= %6.0f Ohms \n", R3);
	printf("R4= %6.0f Ohms \n", R4);
	printf("Vout= %3.1f  V \n", Vout);
	
	return(0);
	}

Ok, the green lines are the ones I'm having trouble with, the compiler says "error: expected ')' before ';' token" for both the lines
And also for the red lines, if I swap them around like so

Code:

Vb = Ve + 0.7
Vout = Vin * Ks

The compiler says "Warning: statement with no effect" and "error: invalid type of 'unary *' " respectively. But if I have them the way I do as above, it works fine.

#defines and semicolons; don't mix.

haha, wow, I can't believe I missed that. I don't even know why I put them in there
Thanks for the help