Thread: Simple issue with bytes

Hi,

I need a byte representation that will allow me to shift right, AND, and compare bytes. I've managed to find this: http://www.informit.com/guides/conte...lus&seqNum=163
which says to use type unsigned char.

For testing purposes, I wish to print the byte in either binary or decimal, it doesn't matter. How would I do that? I've tried using atoi, but it always returns 0. ie:

unsigned char blah = 00000111;
printf("%d", atoi(&blah));

will print 0.

Thanks.

Originally Posted by Todd Burch

It prints 0 because 0b00000111 is not a valid printable ascii number. Valid ascii numbers are 0x30 (0b00110000) through 0x39 (0b00111001).

Yes, but I'm not after the ASCII representation, I want to print either the decimal or binary representation. So how would I do that?

Originally Posted by Todd Burch

Decimal: printf("%d\n", blah) ;

For binary, you'll have to loop 8 times, checking to see if each bit is 1 or zero, and print the appropriate character.

Todd

Ack, I hate the feeling I get when I struggle with something and in the end, the answer is so simple. I thought I tried this, but I must have been only trying to print it as a char. Thanks!

Code:

unsigned char blah = 00000111;

I doubt you can do this. This gave me decimal 73. Nowhere in that link you provided does it say you can do this.

There are numerous .c programs that do just this. The key is which method would you like to use:

1. Bitwise method
2. Recursion
3. using the shift operators '<<' or , '>>'