changing normal array to pointer

[liukinhei]

I have a question about using pointer. Cuz after i use the pointer, the program isnt work.
so i wanna change my orginial code by using pointer
Thank you'

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define merror()   {printf("memory allocation problem\n");exit(1);}

int main(void)
{
	char buffer[100];
	char buf[100][22];
	char sto[19];
	int num;
	int i, j;


	printf(" how many names will be entered : \n");
	fflush(stdout);
	fgets ( buffer, 10,  stdin );
    num = atoi (buffer);

    if (num <=0)
    {
			printf("empty input \n");
	}
	else if (num >100)
	{
			printf("input too long \n");
	}
	else if (num >0 && num <= 100)
	{
			printf("you will enter %d names \n", num);
	}


	for(i=0; i < num; i++)
	{
		printf(" enter a name \n");
		for(j=0; j<21; j++)
		{
		      buf[i][j]=fgetc(stdin);
		      if (buf[i][j]=='\n') {
		        buf[i][j]='\0';
		        break;   /* break j-loop */
		      }
		    }/* end j-loop */

		    if (j==21)
		    {
		      printf("input too long\n");
		      while(fgetc(stdin)!='\n');
		      continue;   /* continue i-loop */
            }
   }

    printf("\nunsorted input:\n");
    for(i=0; i< num; i++)
    printf("%s\n", buf[i]);

for(i=num; i>0; i--)
    for(j=0; j<i; j++)
      if (strcmp(buf[j],buf[j+1])>0) {
        strcpy(sto,buf[j]);
        strcpy(buf[j],buf[j+1]);
        strcpy(buf[j+1],sto);
      }

  printf("sorted input:\n");
  for(i=0; i<=num; i++)
    printf("%s\n",buf[i]);

return 0;
}

[matsp]

		for(j=0; j<21; j++)
		{
		      buf[i][j]=fgetc(stdin);
		      if (buf[i][j]=='\n') {
		        buf[i][j]='\0';
		        break;   /* break j-loop */
		      }
		    }/* end j-loop */

What's wrong with using fgets() for this?

You need to post your pointer code if you want any help on that.

--
Mats