Thread: Array for malloc needed

  1. #1
    Registered User
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    Feb 2008
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    39

    Array for malloc needed

    I am trying to allocate the memory of 1KB of size to two variables. I treied with for loop, but i am getting segmentation fault error. I have attached my sample code below. can anyone help to find why that error occurs and whats the solution for my problem

    Code:
    #include<stdio.h>
    #include<stdlib.h>
    main()
    {
     int i,*par[i];
                                                                                                                                 
      for(i=0;i<=2;i++)
      {
       par[i]=(int *)malloc(1024);
       printf("\n%u",par[i]);
      }
                                                                                  
       free(par);
    }
    "Thanks in advance"

  2. #2
    Registered User
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    Oct 2001
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    2,129
    Code:
    int i,*par[i];
    i is not initialized.
    Code:
    for(i=0;i<=2;i++)
    iterates 3 times.
    Code:
    printf("\n&#37;u",par[i]);
    %u is for unsigned ints, not pointers.

    http://faq.cprogramming.com/cgi-bin/...&id=1043284351

    you don't free your mallocs.

    http://faq.cprogramming.com/cgi-bin/...&id=1043284376
    Last edited by robwhit; 03-10-2008 at 02:21 AM.

  3. #3
    Hurry Slowly vart's Avatar
    Join Date
    Oct 2006
    Location
    Rishon LeZion, Israel
    Posts
    6,788
    int *par[i];
    declares array of unknown size

    int* par[2]; - declares array of 2 pointers
    All problems in computer science can be solved by another level of indirection,
    except for the problem of too many layers of indirection.
    – David J. Wheeler

  4. #4
    Deathray Engineer MacGyver's Avatar
    Join Date
    Mar 2007
    Posts
    3,210
    Code:
    free(par);
    This is NOT supposed to be free()ed. Each element of the array should be free()ed, however.

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