Thread: Converting Base 10 numbers to Base 2, 8, and 16

I'm having trouble writing this program that converts base 10 (decimal) numbers to base 2(binary), base 8(octal), and base 16(hexadecimal). They conver to binary and octal using placeholder notation, however when it comes to converting to base 16/hexadecimal, the program does not read the assigned chars. if you're not familiar with hexadecimal, any number after 9 is assigned a letter (i.e. 10=A, 11=B, 12=C, etc.) it actually converts to hexadecimal, but it just doesn't convert it respectively to the letters after 9.

here's where i'm at:

Code:

#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main()
{
      int a,
          b,
          c,
          d=-1,
          choice;
      char const A=10,
                 B=11,
                 C=12,
                 D=13,
                 E=14,
                 F=15,
                 G=16;

      char ans;

      for(;;)
      {

       printf("Type in any integer to be converted into another base: ");
       scanf("&#37;d",&a);
       printf("Select another base representation (2 or 8 or 16). \n\n2 represents "
              "binary notation\n\n8 represents octal notation\n\n16 represents hexadecimal notation");
       scanf("%d",&choice);

       switch (choice)
       {
        case 2:
             b=a;
             while (b!=0)
             {
              c=b%2;
              b/=2;
              ++d;
              printf("%d x 2^%d\n",c,d);
             }
        break;
        {
         case 8:
              b=a;
              while (b!=0)
              {
               c=b%8;
               b/=8;
               ++d;
               printf("%d x 8^%d\n",c,d);
              }
        break;
        {
         case 16:
              b=a;
              while (b!=0)
              {
               c=b%16;
               b/=16;
               ++d;
               printf("\n%d x 16^%d\n",c,d);
              }
        }
        }
       }

      printf("Do you wish to run again? (Y/N)");
      ans=getchar();
      ans=getchar();

      if (ans=='N')
         break;

      }
      printf("\n");
     
      system("PAUSE");
      return 0;
}

Here's one way:

Code:

if (c < 10)
{
               printf("\n%d x 16^%d\n",c,d);
}
else
{
               printf("\n%c x 16^%d\n",'A'+(c-10), d);
}

G=16; there is no such digit

Originally Posted by krishna

hiiiii this can print any base 10 number to any other base upto 16-base..

You have a horrible indentetion and horrible style

Code:

#include<stdio.h>
static unsigned long int base; /* do not use globals */
int main(void)
{ unsigned long int num;
printf("Enter the Decimal:");scanf("%ld",&num); /* do not place two statements on the same line */
printf("\nNumber and converting Base :");scanf("%ld",&base);
printf("Value of %ld with base of %ld is:",num,base);
convert(num);
getch(); /* this is not standard - and also missing include file - should be removed */
}
convert(unsigned long int num) /* missing return type */
{ if(num){convert(num/base);printf("%c","0123456789ABCDEF"[num%base]);} /* why not to place all you program on same line - it will be even less readable than now */
}

[/QUOTE]