# Simple step part of calculus problem

Printable View

• 11-16-2003
incognito
Simple step part of calculus problem
I have to solve for a.....pethagoryam (sp?) theorem......I forgot how to do this......please help.
• 11-16-2003
Zach L.
Pythagorean ;)

Just use the quadratic formula for equations of the form ax^2+bx+c=0.

Namely, x = (-b + sqrt(b^2 - 4ac))/ (2a) and (-b - sqrt(b^2 - 4ac))/ (2a)
• 11-16-2003
incognito
Thank you...Jesus how could I have not though about this.
• 11-17-2003
Dissata
tk tsk tsk!!!! its + or - the square root;)
• 11-18-2003
Zach L.
Notice the two solutions. ;)
• 11-18-2003
Dissata
doh! slap me for not completely reading it
• 11-19-2003
Felix
Pythagorean... isn't that

(a*a)+(b*b)=(c*c) if it's a right curve or something? I don't know how to say in English :|
• 11-19-2003
the Wookie
a right angle
• 11-19-2003
Zach L.
Quote:

Originally posted by Felix
Pythagorean... isn't that

(a*a)+(b*b)=(c*c) if it's a right curve or something? I don't know how to say in English :|

Yep