# musical notes using sound()

• 02-08-2002
lambs4
musical notes using sound()
where can I find info on using the sound() and delay() to produce musical notes?
• 02-08-2002
Hillbillie
Are you wanting to know how to use them, or how you can use them to make musical notes?
• 02-08-2002
lambs4
I want to know how to use them to make musical notes.
• 02-08-2002
Xterria
ok. sound() will always go until it is stopped. you stop sound() with nosound(). But if you put them right under another you will get no sound:

/////
sound();
nosound();
//////

but if you put delay() between them, the sound will last longer.

////
sound(600);
delay(1000);
nosound();
/////
this will play a semi-high pitch sound for one second.
It is best if you create a function for it:
//////
int music(int pitch, int time)
{
sound(pitch);
delay(time);
nosound();
return(0);
}
/////
so then you can use it like this:

/////
int main()
{
music(600,1000);
return 0;
}
////

which will produce the same sound.
Simple enough?
• 02-08-2002
Imperito
So does anyone know the frequencies of musical notes?

Additionally, does anyone know if it is possible to overlay one frequency of sound with another?
• 02-08-2002
lambs4
Yes, but I was looking for a table of some sort that listed all that information for all of the notes(C,C#,A,etc). I've been studying another language called Turing. It has a function called play() that accepts a string. So play("AB>C<") would play normal A,B, and a high pitch Middle C.
• 02-09-2002
samGwilliam
There is a problem in doing this. A is 440 Hz and every other incarnation of A (in other octaves) is 440 * a power of 2 (880, 1760, etc). This also works in the other direction (220, 110, etc). This applies to every note, therefore the problem is that a semitone (distance between 2 adjecent notes) is different for each adjecent pair. It is in fact logarithmic. Unless you can find some sort of table you are going to have trouble.
• 02-09-2002
lambs4