KingZoolerius66

09-20-2003, 02:40 PM

12:06

1 + 2 + 0 + 6= 9

12 + 6= 18 and 1 + 8= 9

This is true to every minute of everyday.

1 + 2 + 0 + 6= 9

12 + 6= 18 and 1 + 8= 9

This is true to every minute of everyday.

View Full Version : ~~Time Number Theory~

KingZoolerius66

09-20-2003, 02:40 PM

12:06

1 + 2 + 0 + 6= 9

12 + 6= 18 and 1 + 8= 9

This is true to every minute of everyday.

1 + 2 + 0 + 6= 9

12 + 6= 18 and 1 + 8= 9

This is true to every minute of everyday.

KingZoolerius66

09-20-2003, 02:43 PM

04:38PM EST

0 + 4 + 3 + 8= 15 and 1 + 5= 6

4 + 38= 42 and 4 + 2= 6

6 and 6...Hmm.....

0 + 4 + 3 + 8= 15 and 1 + 5= 6

4 + 38= 42 and 4 + 2= 6

6 and 6...Hmm.....

Brian

09-20-2003, 04:33 PM

Hmm.

That's weird

That's weird

KingZoolerius66

09-20-2003, 05:55 PM

7:51PM EST

7 + 5 + 1= 13 and 1 + 3= 4

7 + 51= 58 and 5 + 8= 13 and 1 + 3= 4

7 + 5 + 1= 13 and 1 + 3= 4

7 + 51= 58 and 5 + 8= 13 and 1 + 3= 4

confuted

09-20-2003, 06:08 PM

HOLY CRAP!

Those are some crazy math skills you have there!

Those are some crazy math skills you have there!

joshdick

09-20-2003, 06:33 PM

Originally posted by KingZoolerius66

This is true to every minute of everyday.

I'll truly believe that when I see a proof. My suggestion is to write a program that will execute and display those calculations for every minute. Then, post the code and results. Then, I will be impressed, and I will believe.

This is true to every minute of everyday.

I'll truly believe that when I see a proof. My suggestion is to write a program that will execute and display those calculations for every minute. Then, post the code and results. Then, I will be impressed, and I will believe.

Leeman_s

09-20-2003, 06:43 PM

I'm not flaming you....but:

It really is pointless to call it the time number theory....it's just one of those weird 'number patterns' that have to do with our numbering system being base10.

Take a 3 digit number and do it, a 4 digit, 5 or even a 6 digit number and it still works. Take any fricking number and do it, it will always work. Wow he really pulled the wool over your eyes...

It really is pointless to call it the time number theory....it's just one of those weird 'number patterns' that have to do with our numbering system being base10.

Take a 3 digit number and do it, a 4 digit, 5 or even a 6 digit number and it still works. Take any fricking number and do it, it will always work. Wow he really pulled the wool over your eyes...

Thantos

09-20-2003, 06:50 PM

Convert it to base octo and then see if it works :)

ZerOrDie

09-20-2003, 06:51 PM

Originally posted by joshdick

I'll truly believe that when I see a proof. My suggestion is to write a program that will execute and display those calculations for every minute. Then, post the code and results. Then, I will be impressed, and I will believe.

Majors: Mathematics and Computer Science

you would think a math major would want to prove it mathematically... would you prove anything even if it works for all base 10 numbers?

I'll truly believe that when I see a proof. My suggestion is to write a program that will execute and display those calculations for every minute. Then, post the code and results. Then, I will be impressed, and I will believe.

Majors: Mathematics and Computer Science

you would think a math major would want to prove it mathematically... would you prove anything even if it works for all base 10 numbers?

Leeman_s

09-20-2003, 07:03 PM

You guys do get what I mean, right? It works for all numbers, and has nothing to do with time.

JaWiB

09-20-2003, 08:34 PM

12:00

1+2+0+0=3

12+0+0=12

1+2+0+0=3

12+0+0=12

confuted

09-20-2003, 08:49 PM

Originally posted by Leeman_s

You guys do get what I mean, right? It works for all numbers, and has nothing to do with time.

Yes; it's the basis for quickly testing whether a number is evenly divisible by 3 or 9.

If the sum of the digits is evenly divisible by 3 or 9, the original number is as well. If you're dealing with insanely large numbers, you can sum the digits of the sum of the digits of the original number, ad infinitum.

You guys do get what I mean, right? It works for all numbers, and has nothing to do with time.

Yes; it's the basis for quickly testing whether a number is evenly divisible by 3 or 9.

If the sum of the digits is evenly divisible by 3 or 9, the original number is as well. If you're dealing with insanely large numbers, you can sum the digits of the sum of the digits of the original number, ad infinitum.

KingZoolerius66

09-20-2003, 09:18 PM

12:00

1+2+0+0=3

12+0+0=12

You did it wrong.

12:00PM EST

1 + 2 + 0 + 0= 3;

12 + 0= 12 and 1 + 2= 3;

1+2+0+0=3

12+0+0=12

You did it wrong.

12:00PM EST

1 + 2 + 0 + 0= 3;

12 + 0= 12 and 1 + 2= 3;

joshdick

09-20-2003, 11:43 PM

Originally posted by ZerOrDie

Majors: Mathematics and Computer Science

you would think a math major would want to prove it mathematically... would you prove anything even if it works for all base 10 numbers?

Yeah, it'd prove that it works for all times of the day :rolleyes:

I'd love to prove it mathematically, put I have neither the time nor the capability. However, I know it'd be quite easy to write a program to prove this theory for all cases.

Majors: Mathematics and Computer Science

you would think a math major would want to prove it mathematically... would you prove anything even if it works for all base 10 numbers?

Yeah, it'd prove that it works for all times of the day :rolleyes:

I'd love to prove it mathematically, put I have neither the time nor the capability. However, I know it'd be quite easy to write a program to prove this theory for all cases.

nickname_changed

09-21-2003, 12:23 AM

12:08

1 + 2 + 0 + 8 = 11

12 + 08 = 20

2 + 0 = 2

Doesn't work out.....

1 + 2 + 0 + 8 = 11

12 + 08 = 20

2 + 0 = 2

Doesn't work out.....

nickname_changed

09-21-2003, 12:31 AM

Seems any numbers that add up to 20 dont work out.

11:09

1 + 1 + 0 + 9 = 11

11 + 9 = 20

2 + 0 = 2

What if they are higher than 20?

12:09

1 + 2 + 0 + 9 = 12

12 + 09 = 21

2 + 1 = 3

What about 22

12:10

12+10 = 22, 2+2 = 4

1 + 2 + 1 + 0 = 4

So it seems anything thats 20>21 doesn't work out that way.

11:09

1 + 1 + 0 + 9 = 11

11 + 9 = 20

2 + 0 = 2

What if they are higher than 20?

12:09

1 + 2 + 0 + 9 = 12

12 + 09 = 21

2 + 1 = 3

What about 22

12:10

12+10 = 22, 2+2 = 4

1 + 2 + 1 + 0 = 4

So it seems anything thats 20>21 doesn't work out that way.

Sang-drax

09-21-2003, 04:56 AM

Originally posted by stovellp

12:08

1 + 2 + 0 + 8 = 11

12 + 08 = 20

2 + 0 = 2

Doesn't work out.....

Umm...

1 + 2 + 0 + 8 = 11

1 + 1 = 2

12 + 08 = 20

2 + 0 = 2

12:08

1 + 2 + 0 + 8 = 11

12 + 08 = 20

2 + 0 = 2

Doesn't work out.....

Umm...

1 + 2 + 0 + 8 = 11

1 + 1 = 2

12 + 08 = 20

2 + 0 = 2

nickname_changed

09-21-2003, 06:08 AM

But thats doing it differently. The first example he gave only split the second number (the 12+06) but didn't split the first number (1+2+0+6).

Sang-drax

09-21-2003, 06:14 AM

OK, here's a proof that I made (I had nothing to do; I had to shut down the computer due to a thunderstorm :) )

It proves that King Zoolerius ther ory is correct for any two number os any length in any base.

S(X) is the digit sum of X

B is the base

If X is a number of length n in base B, X can be written as

X = B^0 * x0 + B^1 * x1 + ... + B^n * xn

then S(X) is calculated as follows

S(X) = S(x0+x1+...+xn) if X >= B (*)

S(X) = X if X<B

Now, if we choose two arbitrary numbers X and Y, if King Zoolerius' theory is correct, then:

S(X+Y) = S(x0+x1+...+xn + y0+y1+...+yn)

S(X+Y) = S[ B^0*(x0+y0) + B^1*(x1+y1) + ... + B^n*(xn+yn) ]

but we earlier concluded (*) that this could we written as

S(x0+y0+x1+y1+...+xn+yn)which is just what we was going to show.

This has obviously nothing to do with base 10, here's an example with hexadecimal numbers:

X = EF361AA

Y = 518204B

E+F+3+6+1+A+A + 5+1+8+2+0+4+B = 5A and 5+A = F

EF361AA + 518204B = 140B81F5 and 1+4+0+B+8+1+F+5 = 2D and 2+D = F

Originally posted by stovellp

But thats doing it differently. The first example he gave only split the second number (the 12+06) but didn't split the first number (1+2+0+6).

You cannot split a single digit (9), can you?

You split every number larger than of equal to the current base.

It proves that King Zoolerius ther ory is correct for any two number os any length in any base.

S(X) is the digit sum of X

B is the base

If X is a number of length n in base B, X can be written as

X = B^0 * x0 + B^1 * x1 + ... + B^n * xn

then S(X) is calculated as follows

S(X) = S(x0+x1+...+xn) if X >= B (*)

S(X) = X if X<B

Now, if we choose two arbitrary numbers X and Y, if King Zoolerius' theory is correct, then:

S(X+Y) = S(x0+x1+...+xn + y0+y1+...+yn)

S(X+Y) = S[ B^0*(x0+y0) + B^1*(x1+y1) + ... + B^n*(xn+yn) ]

but we earlier concluded (*) that this could we written as

S(x0+y0+x1+y1+...+xn+yn)which is just what we was going to show.

This has obviously nothing to do with base 10, here's an example with hexadecimal numbers:

X = EF361AA

Y = 518204B

E+F+3+6+1+A+A + 5+1+8+2+0+4+B = 5A and 5+A = F

EF361AA + 518204B = 140B81F5 and 1+4+0+B+8+1+F+5 = 2D and 2+D = F

Originally posted by stovellp

But thats doing it differently. The first example he gave only split the second number (the 12+06) but didn't split the first number (1+2+0+6).

You cannot split a single digit (9), can you?

You split every number larger than of equal to the current base.

KingZoolerius66

09-21-2003, 09:52 AM

Finally!, someone who supports and agrees with my theory!! I love you Sang-drax!!!

joshdick

09-21-2003, 11:21 AM

Huzzah, SangDrax. Good job.

Leeman_s

09-21-2003, 01:36 PM

I agreed with you, ok I was wrong about the base10 thing. But what I'm pointing out is that it has NOTHING to do with TIME, king zoolerius.

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