Okay here is a chemistry problem that I have done, I wanted to check it with other people...btw this stuff is really hard to me so don't be too critical...
The problem:
there are 6.02E23 atoms of mercury in 201g of mercury, the density of mercury is 13.5g/mL. What is the volume of the same liquid, in micro m3, occupied by one atom of mercury?
My final solution:
One atom takes up:
2.45E-23 mL
How I solved it:
If 201g of mercury has 6.02E23 atoms, then 13.5g of mercury must have 6.02E23 / (201/13.5)
NumberOfAtoms = 6.02E23 / (201/13.5)
NumberOfAtoms = NumberOfAtoms * (1mL / NumberOfAtoms)
Do you think I'm correct? Chemistry sucks