I'm guessing that X2Y means (X^2) * YNot sure where you get the first two lines of that... oh, 2 equations, 2 unknowns...Originally posted by Unregistered
x = (9 - (41)^0.5) / 2, y = (9 + (41)^0.5) / 2
OR
x = (9 + (41)^0.5) / 2, y = (9 - (41)^0.5) / 2
so x^2 + y^2 = 61
also like this:
xy = 10
x^2 y + xy^2 + x + y = 99
10x + 10y + x + y = 99
11x + 11y = 99
x + y = 9
(x + y)^2 = 81
x^2 + 2xy + y^2 = 81
x^2 + y^2 + 2(10) = 81
x^2 + y^2 = 61
This is my signature. Remind me to change it.
correct answer.
and a very amusing quote indeed!"There are 10 kinds of people in this world. Those who understand binary, and those who don't."
I am the Alpha and the Omega!!!
I find binary much easier than octal and hex for example.
Btw, is there any manipulator in C++ for binary?
Example:
Code:cout << hex << 16;
Nope. You will have to write one yourself.
Cool
X > Y
Z + Q = X + Y
Z + X < Q + Y
Rank X,Y,Z,Q from highest to lowest
Q, X, Y, Z
X > Y
Z + X < Q + Y
From the above 2 lives it should be obvious that:
Q > Z, because we add the bigger (X) to Z ans it' still smaller then the sum of smaller (Y) and Q
so,
X > Y
Q > Z
Z + X < Q + Y
-Z - Q = -X - Y
X - Q < Q - X
2X < 2Q
X < Q
so Q > X > Y and Q > Z >> Q is biggest
...but: Z + Q = X + Y
since Q is biggest and X > Q, Y must be bigger then Z...
So Z is smallest form Q > X > Y and Z < Y
biggest to smallest: Q, X, Y, Z
is it a coinsidence that they are in alphabetical order?
This is my signature. Remind me to change it.
ok. here is another one:
and you better provide an explanation...Code:Let K be a constant, and the following a polynomial equation in x: x4 + Kx3 + 11x2 + 7x -12 = 0 What is the sum of the reciprocals of the roots of this equation?
I am the Alpha and the Omega!!!
no one wants to try?
is it too hard?
I am the Alpha and the Omega!!!
7/12
greetinx,
alex
I've got one for you. It's more of a brain teaser than a math problem but my math teacher gave it to me. All you have to do is give the next three lines in this series of numbers:
1
11
21
1211
...
...
...
1
11
21
1211
111221
312211
13112221
I won't explain the answer cuz I want others to figure it out too.
Wow, that was really fast. I thought it would take longer.
13112221
[cont...]
1113213211
31131211131221
13211311123113112211
and so on
I can figure the first two rows out, they go like:
1
11
21
12
11
31
13
11
11
41
14
.
.
.
.
.
right?
