oh ****, my bad, that's what i got too....guess i was thinking about the (-6) when I was writing it
to be exact, if h=height,
Code:(h)(pi)(3^2)=792(pi)/10 or, h=8.8 TF, height should be increased by .8
oh ****, my bad, that's what i got too....guess i was thinking about the (-6) when I was writing it
to be exact, if h=height,
Code:(h)(pi)(3^2)=792(pi)/10 or, h=8.8 TF, height should be increased by .8
i got it in an easier way. i did not even get anything like 792.
i got:
3(pi)x=2.4(pi)
.: x= 2.4 / 3
.: x=0.8
I am the Alpha and the Omega!!!
here's a problem for ya
Code:if x is a number that satisfies ____ _____ \3|x+9 - \3| x-9 = 3 \| \| find the value of X^2
I found a easier way to write that problem
Code:if [(x+9)^(1/3)] - [(x-9)^(1/3)] = 3 what's x^2?
Last edited by Commander; 05-24-2002 at 07:54 PM.
or we can increase the diameter by:
0.292853089
ps: i am not so sure about that
Last edited by Jet_Master; 05-24-2002 at 07:37 PM.
I am the Alpha and the Omega!!!
that's what i got...
i just checked both answers and they are both exactly correct.
whoo hoo!
I am the Alpha and the Omega!!!
commander, i am still doing your math ques. it is kinda hard... i have to find the formula now...
where is it...? oh man , where is it???
**looking...**
I am the Alpha and the Omega!!!
The current volume of the glass is:
Formula: Base area*height/3
Diameter/2=r, in this case 3cm. base area= r^2*3.14, which in this case becomes 28.26 cm2.
28.26*8=226.08; 226.08/3=75.36. The glass can currently keep a volume of 75.36cm3.
The manufacturers wants it to be able to keep 10% more, 75.36*1.1=82.896
For you guys, I think this is a really easy problem. Hope I cleared things up here.
me and commander already got the answer long time ago... it is posted a few posts before..
anyway here it is again:
we can increase the height by 0.8 cm
or we can increase the diameter by 0.292853089 cm
I am the Alpha and the Omega!!!
Here's another one for you:
A coconut has the shape of a ball. It has a diameter of 11cm. It has a shell which is 48mm thick, all around. How big part of the coconut consists of the shell? Please answer in %
Last edited by Zewu; 05-25-2002 at 09:22 AM.
How much volume is the shell out of the coconut?
More milk please...
MisterBadger says:
Using pi to 7dp, working in millimetres:
radius of sphere, r = 55mm
Volume of sphere = 4/3*pi*r*r*r;
Overall Volume = 4/3 * 3.1415926 * 55 * 55 * 55;
= 696909.89 cubic millimetres;
Non-shell radius = (110 - 96)/2 = 7mm;
Non-shell Volume = 4/3 * 3.1415926 * 7 * 7 * 7;
= 1436.75 cubic millimetres;
Overall Volume - Non-shell Volume = Shell Volume;
Shell Volume = 696909.89 - 1436.75 = 695473.14 cubic millimetres;
(695473.14 / 696909.89) * 100 = 99.794 %
Hoping I'm right, but disappointed about the lack of milk!
Cheers from Badger - off to cool a tired brain
I think you'll find this answer to be kind of interesting:I know, I know, not much of a math problem, although...If a 6ft tall person walks around the equator of Jupiter, how much more did his head travel than his feet?
This is my signature. Remind me to change it.
Noone could answer this one? want me to post the ans?Code:if [(x+9)^(1/3)] - [(x-9)^(1/3)] = 3 what's x^2?
