oh ****, my bad, that's what i got too....guess i was thinking about the (-6) when I was writing it
to be exact, if h=height,
Code:(h)(pi)(3^2)=792(pi)/10 or, h=8.8 TF, height should be increased by .8
oh ****, my bad, that's what i got too....guess i was thinking about the (-6) when I was writing it
to be exact, if h=height,
Code:(h)(pi)(3^2)=792(pi)/10 or, h=8.8 TF, height should be increased by .8
i got it in an easier way. i did not even get anything like 792.
i got:
3(pi)x=2.4(pi)
.: x= 2.4 / 3
.: x=0.8
I am the Alpha and the Omega!!!
here's a problem for ya
Code:if x is a number that satisfies ____ _____ \3|x+9 - \3| x-9 = 3 \| \| find the value of X^2
I found a easier way to write that problem
Code:if [(x+9)^(1/3)] - [(x-9)^(1/3)] = 3 what's x^2?
Last edited by Commander; 05-24-2002 at 07:54 PM.
or we can increase the diameter by:
0.292853089
ps: i am not so sure about that
Last edited by Jet_Master; 05-24-2002 at 07:37 PM.
I am the Alpha and the Omega!!!
that's what i got...
i just checked both answers and they are both exactly correct.
whoo hoo!
I am the Alpha and the Omega!!!
commander, i am still doing your math ques. it is kinda hard... i have to find the formula now...
where is it...? oh man , where is it???
**looking...**
I am the Alpha and the Omega!!!
The current volume of the glass is:
Formula: Base area*height/3
Diameter/2=r, in this case 3cm. base area= r^2*3.14, which in this case becomes 28.26 cm2.
28.26*8=226.08; 226.08/3=75.36. The glass can currently keep a volume of 75.36cm3.
The manufacturers wants it to be able to keep 10% more, 75.36*1.1=82.896
For you guys, I think this is a really easy problem. Hope I cleared things up here.
me and commander already got the answer long time ago... it is posted a few posts before..
anyway here it is again:
we can increase the height by 0.8 cm
or we can increase the diameter by 0.292853089 cm
I am the Alpha and the Omega!!!
![]()
Here's another one for you:
A coconut has the shape of a ball. It has a diameter of 11cm. It has a shell which is 48mm thick, all around. How big part of the coconut consists of the shell? Please answer in %
Last edited by Zewu; 05-25-2002 at 09:22 AM.
MisterBadger says:
Using pi to 7dp, working in millimetres:
radius of sphere, r = 55mm
Volume of sphere = 4/3*pi*r*r*r;
Overall Volume = 4/3 * 3.1415926 * 55 * 55 * 55;
= 696909.89 cubic millimetres;
Non-shell radius = (110 - 96)/2 = 7mm;
Non-shell Volume = 4/3 * 3.1415926 * 7 * 7 * 7;
= 1436.75 cubic millimetres;
Overall Volume - Non-shell Volume = Shell Volume;
Shell Volume = 696909.89 - 1436.75 = 695473.14 cubic millimetres;
(695473.14 / 696909.89) * 100 = 99.794 %
Hoping I'm right, but disappointed about the lack of milk!
Cheers from Badger - off to cool a tired brain![]()
I think you'll find this answer to be kind of interesting:I know, I know, not much of a math problem, although...If a 6ft tall person walks around the equator of Jupiter, how much more did his head travel than his feet?![]()
This is my signature. Remind me to change it.
Noone could answer this one? want me to post the ans?Code:if [(x+9)^(1/3)] - [(x-9)^(1/3)] = 3 what's x^2?