I guess that would work...
I would have just used sequential Bayes
(I.E. ask two dwarfs which is the right path and use sequential Bayes to calculate the probability of each being the actual correct one)
I guess that would work...
I would have just used sequential Bayes
(I.E. ask two dwarfs which is the right path and use sequential Bayes to calculate the probability of each being the actual correct one)
Last edited by CornedBee; 03-28-2009 at 11:40 AM.
Why? Only one person will answer? :P I thought just ask all three of them at the same time. It's really just one question... And if all three of them answer, you're done.
Last edited by CornedBee; 03-28-2009 at 11:40 AM.
Last edited by CornedBee; 03-28-2009 at 11:40 AM.
All things begin as source code.
Source code begins with an empty file.
-- Tao Te Chip
Like I said before:
Which way would the one of you that always speaks the truth say you would say I'd have to go?
The one who always speaks the truth would speak the truth about the way and point the proper direction.
The one who always lies knows the one who would speak the truth would tell he'd say the wrong direction. But he lies about that fact, so he points to the proper direction.
The one who sometimes speaks the truth is undecided.
So two always point to the proper way.
If all three answer, two point you to the right way, and the other you don't know... And the riddle doesn't say only one dwarf will answer your question :P.
Last edited by CornedBee; 03-28-2009 at 11:41 AM.
Well, now you can imagine why nobody will let me do mental arithmetic...
I hereby establish that only one dwarf is allowed to answer per question.
Greets from Graz,
Philip
Last edited by CornedBee; 03-28-2009 at 11:41 AM.
All things begin as source code.
Source code begins with an empty file.
-- Tao Te Chip