argv[0] with WinMain()

This is a discussion on argv[0] with WinMain() within the Windows Programming forums, part of the Platform Specific Boards category; Is there a way to access the equivilent of argv[0] when you have WinMain()? In other words, is there a ...

  1. #1
    Frequently Quite Prolix dwks's Avatar
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    argv[0] with WinMain()

    Is there a way to access the equivilent of argv[0] when you have WinMain()?

    In other words, is there a Windows function to return the name of the executable?
    dwk

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  2. #2
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    I Think

    Please someone correct me if I'm wrong =P but I think the equivalent is LPSTR

    Code:
    int WINAPI WinMain(HINSTANCE,HISTANCE,LPSTR,int);
    You could always use the function GetModuleFileName

    example from winprog.org's site:

    Code:
            case WM_LBUTTONDOWN:
            {
                char szFileName[MAX_PATH];
                HINSTANCE hInstance = GetModuleHandle(NULL);
    
                GetModuleFileName(hInstance, szFileName, MAX_PATH);
                MessageBox(hwnd, szFileName, "This program is:", MB_OK | MB_ICONINFORMATION);
            }
            break;
    Last edited by Homunculus; 03-05-2006 at 11:15 AM.

  3. #3
    Registered User mrafcho001's Avatar
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    no..

    LPSTR lpCmdLine is used for any parameters passed to the program, or if you drag and drop a file on the program it will have the path of the file.
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    Just use GetModuleFileName, and pass NULL as the first parameter. If you need the rest of the arguments, use GetCommandLine or the lpCmdLine variable passed to WinMain().

  5. #5
    Frequently Quite Prolix dwks's Avatar
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    Thanks.
    dwk

    Seek and ye shall find. quaere et invenies.

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    "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra
    "The only real mistake is the one from which we learn nothing." -- John Powell


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