Ok yeah that didn't sound like an API function.. I found this code:
Code:
BYTE* Get24BitPixels(HBITMAP pBitmap, WORD *pwWidth, WORD *pwHeight)
{
// a bitmap object just to get bitmap width and height
BITMAP bmpBmp;
// pointer to original bitmap info
LPBITMAPINFO pbmiInfo;
// bitmap info will hold the new 24bit bitmap info
BITMAPINFO bmiInfo;
// width and height of the bitmap
WORD wBmpWidth, wBmpHeight;
// ---------------------------------------------------------
// get some info from the bitmap
// ---------------------------------------------------------
GetObject(pBitmap, sizeof(bmpBmp),&bmpBmp);
pbmiInfo = (LPBITMAPINFO)&bmpBmp;
// get width and height
wBmpWidth = (WORD)pbmiInfo->bmiHeader.biWidth;
wBmpWidth -= (wBmpWidth%4); // width is 4 byte boundary aligned.
wBmpHeight = (WORD)pbmiInfo->bmiHeader.biHeight;
// copy to caller width and height parms
*pwWidth = wBmpWidth;
*pwHeight = wBmpHeight;
// ---------------------------------------------------------
// allocate width * height * 24bits pixels
BYTE *pPixels = new BYTE[wBmpWidth*wBmpHeight*3];
if (!pPixels) return NULL;
// get user desktop device context to get pixels from
HDC hDC = GetWindowDC(NULL);
// fill desired structure
bmiInfo.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
bmiInfo.bmiHeader.biWidth = wBmpWidth;
bmiInfo.bmiHeader.biHeight = -wBmpHeight;
bmiInfo.bmiHeader.biPlanes = 1;
bmiInfo.bmiHeader.biBitCount = 24;
bmiInfo.bmiHeader.biCompression = BI_RGB;
bmiInfo.bmiHeader.biSizeImage = wBmpWidth*wBmpHeight*3;
bmiInfo.bmiHeader.biXPelsPerMeter = 0;
bmiInfo.bmiHeader.biYPelsPerMeter = 0;
bmiInfo.bmiHeader.biClrUsed = 0;
bmiInfo.bmiHeader.biClrImportant = 0;
// get pixels from the original bitmap converted to 24bits
int iRes = GetDIBits(hDC,pBitmap,0,wBmpHeight,(LPVOID)pPixels,&bmiInfo,DIB_RGB_COLORS);
// release the device context
ReleaseDC(NULL,hDC);
// if failed, cancel the operation.
if (!iRes)
{
delete pPixels;
return NULL;
};
// return the pixel array
return pPixels;
}
From this article.
[edit]
Oops Salem beat me in with the same tactics.
[/edit]