Thread: GetOpenFileName

what do you mean it doesn't work?

theoretically those both work the same way....

here's a clearer example:

Code:

 if(int a=1)
    cout << "blah" << endl;
 if(1)
    cout << "blah 22";

in the first example, it does the following:

1) creates the variable a, as an int
2) assigns a to 1
3) tests the value of a, which is 1, therefor becoming true, and outputting blah

in the second one, it does this:

1) tests if 1...is true...duh
2) outputs blah 22

so i don't see how your code above could be "not working" but i also don't know what you mean by "not working"

silk.odyssey, In the first code you posted it is allways true, but in the 2nd one GetOpenFileName, has a chance of being 0.

Not necessarily true hollowlife, notice that it's not testing if GetOpenFileName was assigned correctly to the variable, but that it's actually testing the result of what's in the variable after the assignment operation.

Here's a test i did to show what i mean:

Code:

 #include <iostream.h>
 
 int func(int test)
 {
 	return test;
 }
 
 int main()
 {
 	if(int a=func(1))	// Evaluates to 1, so it's true
 		cout << "yo";
 	if(int a=func(0))	// Evaluates to 0, so it's false
 		cout << "yo 2";
 	return 0;
 }

the output from this program is:

yo

Hmm, I could of swore that was what caused a bug with one of my programs, but just ignore my last post.