Wm_mdigetactive??

**SuperNewbie** · 11-20-2003

Hi:

I have a problem like this:

In MDI, there are several Child windows, they are opened when frame window created...

Code:

....WinProc() //frame window proc...
char szBuf[20]; // to hold activated child window name.
HWND hwndChild;


in message handler, 
switch (mMsg)
{
.......

default:

// get the active child window handle
hwndChild = (HWND)SendMessage (hwndClient,     MDIGETACTIVE, 0, 0);

//get the active child window title name
GetW indowText(hwndChild,szBuf,20);

//display the title name
MessageBox(0,szBuf,"window title",MB_OK);

it pops up the message only when I click the submenu item, but it always give the previous active child window title name... I don't how to solve that...

And how can I get the active child window name only by clicking the child window, not from submenu item??
Thanks

I want to get the active Child window's title name when I simply click one child window,

**Codeplug** · 11-20-2003

Your code is probably running before the child window becomes active. That's why you're getting the "previous" active child.

Try running your code after DefWindowProc().

gg

**tyouk** · 11-20-2003

You could also try to place your code above the switch(Msg) line thus you always get the active window, however, this leads to other problems incase you receive a WM_SETFOCUS or WM_KILLFOCUS message in which case your "active window" code would be wrong.

Why not just inside of a WM_KILLFOCUS message, wParam holds the handle to the window receiving the focus. Thus just set it as so...

Code:

case WM_KILLFOCUS:
        hActiveWnd = (HWND)wParam;
        // other code here
        return(DefMDIWndProc(hwnd, Msg, wParam, lParam);
        break;

that way you always get the active window, and you don't have to reset a variable (even when not needed) everytime a message comes in?

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