Overloading a pointer to a class

I don't think it's possible, but can I overload a pointer to a class? Ie:

Code:

---

class M
{
public:
    M *operator *= (M *);
};

M *M::operator *= (M *param)
{
    //Do things by dereferencing
    return this;
}

void func(M *a,M *b)
{
    a*=b; //This would give characteristics of b to a
}

---

The operation I want performed has nothing to do with multiplication - it's just a random pick of operator. So, is this possible? I tried it like the above, without success, but maybe I have the syntax wrong?

No. A pointer is a pointer. Not an object.

gg

[EDIT]
Using "->" or "*" on a pointer will always dereference (ie. not call a method). Otherwise, it's just a 32 (or 64) bit value.

Ok then, let's say I overload the class (and I did). I'm now doing this:

Code:

---

void Func(M *a,M *b)
{
    (*a) *= (*b);
}

---

Is that the best way to manipulate the pointers?

You could use references:

Code:

---

void Func(M &a, M &b)
{
    a *= b;
}

---

gg

Ok, cheers, I should be alright with that for now.