A small problem with TextOut()

This is a discussion on A small problem with TextOut() within the Windows Programming forums, part of the Platform Specific Boards category; Hi, I have this string " line1\nline2\nline3\n ", that I would like to print out with TextOut() , but since ...

  1. #1
    * Death to Visual Basic * Devil Panther's Avatar
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    A small problem with TextOut()

    Hi, I have this string "line1\nline2\nline3\n", that I would like to print out with TextOut(), but since TextOut() doesn't support '\n', I had to make it myself.
    And It does print "line1" and under it "line2", but that's it, why?
    Where is "line3"?

    "line1\nline2\nline3\n" is been passed inside msg

    Code:
    void preview_text(HDC hDC, int x, int y, char *msg)
     {
       int i, j=0;
       char line[100]={0}; 
    
       for (i=0; i<strlen(msg); ++i)
        {
          if (msg[i]=='\n')
           {
             TextOut(hDC, x, y, line, strlen(line));
             memset(line, '\0', 100);
             y += 13;
             j = 0;
           }
          else
            line[j++] = msg[i];
        }
     }

    Thanks.
    "I don't suffer from insanity but enjoy every minute of it" - Edgar Allen Poe

    http://www.Bloodware.net - Developing free software for the community.

  2. #2
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    if you don't want to go threw all that you could try using DrawText i think that allows the \n's

  3. #3
    * Death to Visual Basic * Devil Panther's Avatar
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    Thanks, I will check that out... But still what's wrong with this code? It suppost to work right.
    "I don't suffer from insanity but enjoy every minute of it" - Edgar Allen Poe

    http://www.Bloodware.net - Developing free software for the community.

  4. #4
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    code:-----------------------------------------------------------------------------

    void preview_text(HDC hDC, int x, int y, char *msg)
    {
    int i, j=0;
    char line[100]={0};

    for (i=0; i<strlen(msg); ++i)
    {
    if (msg[i]=='\n')
    {
    TextOut(hDC, x, y, line, strlen(line));
    memset(line, '\0', 100);
    y += 13;
    j = 0;
    }
    else
    line[j++] = msg[i];
    }
    }
    --------------------------------------------------------------------------------

    Your code is looking perfect. Pls check the strings's entirety at the place from where you are calling this function.

    I mean whether this function get "line1\nline2\nline3\n" or "line1\nline2\nline3" ?
    Chintan R Naik

  5. #5
    * Death to Visual Basic * Devil Panther's Avatar
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    the input!!! of course... it only calls for TextOut() when it sees '\n'...

    Thanks.
    "I don't suffer from insanity but enjoy every minute of it" - Edgar Allen Poe

    http://www.Bloodware.net - Developing free software for the community.

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