Printing: The Lazy Way

Is there some free SDK or library that I can download that has printing functions that get rid of the need of everything except a couple lines of code when I need to print?

Originally posted by face_master
Is there some free SDK or library that I can download that has printing functions that get rid of the need of everything except a couple lines of code?

This is something I posted on another thread....its only a little code...and half of it is to diplay that nice print dialog.........

Your best bet is to spend an hour reading the actual functions in the SDK......IMHO, it will take just as long to grasp the usage of a 3rd party lib.....and I think its less hassle

Code:

#include <string>//I am lazy when it comes to char arrays
using std::string;
#include <windows.h>//The all important header
#include <commdlg.h>//Dont forget comdlg32.lib!!!

int WINAPI WinMain(HINSTANCE,HINSTANCE,LPSTR,int)
{
PRINTDLG  pd;//To initialise dialog & accept results
string str = "API rules!! :p";//catchy phrase
DOCINFO di = {
sizeof(DOCINFO),
"Fordy's Doc",
NULL
};//This gives details on doc...like its name when spooled

ZeroMemory(&pd,sizeof(PRINTDLG));//saves initiliasing to zero

pd.lStructSize = sizeof(PRINTDLG);
pd.hwndOwner = HWND_DESKTOP;
pd.Flags = PD_RETURNDC;//This gives DC to printer selected
pd.nCopies = 1;


if(!PrintDlg(&pd))
return 0;//If the user cancels....?

if(StartDoc(pd.hDC,&di)>0 && StartPage(pd.hDC)>0){//new doc...new page
TextOut(pd.hDC,10,10,str.c_str(),str.length()); //Write some text
EndPage(pd.hDC);//end of page
EndDoc(pd.hDC); //end of doc
}
  DeleteDC(pd.hDC);//Clean up!

  return 0;
}

Thanks, I try that!

I just have on question, to avoid heaps of confusion, could you please tell me how to replace this call using a character array instead of a string please?

Code:

TextOut(pd.hDC,10,10,str.c_str(),str.length());

Originally posted by face_master
I just have on question, to avoid heaps of confusion, could you please tell me how to replace this call using a character array instead of a string please?

Code:

TextOut(pd.hDC,10,10,str.c_str(),str.length());

Code:

char* buff = "Hello World";
int nLen = strlen(buff);

TextOut(pd.hDC,10,10,buff,nLen);

Thanks.