Why no voice?

This is a discussion on Why no voice? within the Windows Programming forums, part of the Platform Specific Boards category; My english is poor,so I beg your pardon. My codes are about playing voice,and it doesn't return error, but it ...

  1. #1
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    Why no voice?

    My english is poor,so I beg your pardon.
    My codes are about playing voice,and it doesn't return error,
    but it has no voice,why?
    Look:
    Code:
    #define OUT_BUFFER_SIZE 6000
    void main()  
    {
    
    	HWAVEOUT     hWaveOut ;
    	PWAVEHDR     pWaveHdr ;
    	WAVEFORMATEX waveformat ;
    	PBYTE        pBuffer;
    	
    	waveformat.wFormatTag      = WAVE_FORMAT_PCM ;
    	waveformat.nChannels       = 2 ;
    	waveformat.nSamplesPerSec  = 44100; ;
    	waveformat.nAvgBytesPerSec = 44100*16*2/8 ;
    	waveformat.nBlockAlign     = 16*2/8 ;
    	waveformat.wBitsPerSample  = 16 ;
    	waveformat.cbSize          = 0 ;
    	
    	
    	
    	// open   
    	if (waveOutOpen (&hWaveOut, WAVE_MAPPER, &waveformat,0, 0, 0)!= MMSYSERR_NOERROR)
    	{
    		printf("waveOutOpen error \n");
    		return ;
    	}
    	
        
    	pWaveHdr =(PWAVEHDR)malloc (sizeof (WAVEHDR)) ;
            pBuffer  = (PBYTE)malloc (OUT_BUFFER_SIZE) ;
    	
    	// prepare buffer   
            pWaveHdr->lpData          = (char*)pBuffer ;
    	pWaveHdr->dwBufferLength  = OUT_BUFFER_SIZE ;
    	pWaveHdr->dwBytesRecorded = 0 ;
    	pWaveHdr->dwUser          = 0 ;
    	pWaveHdr->dwFlags         = 0 ;
    	pWaveHdr->dwLoops         = 1 ;
    	pWaveHdr->lpNext          = NULL ;
    	pWaveHdr->reserved        = 0 ;
    	
           if(waveOutPrepareHeader(hWaveOut, pWaveHdr,sizeof (WAVEHDR))!=MMSYSERR_NOERROR) 
    	{
    		printf("waveOutPrepareHeader error \n");
    		return ;
    	}
    	// play   
    	memset(pBuffer,70,OUT_BUFFER_SIZE);
    	if(waveOutWrite (hWaveOut, pWaveHdr, sizeof (WAVEHDR)) !=MMSYSERR_NOERROR) 
    	{
    		printf("waveOutWrite error \n");
    		return ;
    	}
    	
    	// clean   
           if(waveOutReset(hWaveOut) !=MMSYSERR_NOERROR)
    	{
    		printf("waveOutReset error \n");
    		return ;
    	}
    
          if(waveOutUnprepareHeader (hWaveOut, pWaveHdr, sizeof (WAVEHDR)) !=MMSYSERR_NOERROR)
    	{
    		printf("waveOutUnprepareHeader error \n");
    		return ;
    	}
    
           if(waveOutClose(hWaveOut)!=MMSYSERR_NOERROR)
    	{
    		printf("waveOutClose error \n");
    		return ;
    	}
    }

  2. #2
    and the hat of wrongness Salem's Avatar
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    Pulse-code modulation - Wikipedia, the free encyclopedia
    You get noise, by having changes in the data.

    > memset(pBuffer,70,OUT_BUFFER_SIZE);
    6K of constant values is boring.
    Try filling it with random values, or maybe a chunk of a suitably encoded wav file.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  3. #3
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    Is your "voice" data recorded in a wave file of some kind?

    If so, just use the PlaySound() API.

    If you are trying to generate voice programattically by wave output, you are in for one BIG job... Not only will you need to assemble phonetic samples in several variations, you will need to play those samples in response to text... that is you will need to parse "This is a test" (for example) into it's 8 phonetic components and play them one after the other. Major software houses have worked on this technology for years and are only now getting it so the voice sounds natural enough to not irritate people...

    Microsoft Speech Technologies
    Last edited by CommonTater; 11-24-2011 at 10:36 PM.

  4. #4
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    Quote Originally Posted by Salem View Post
    Pulse-code modulation - Wikipedia, the free encyclopedia
    You get noise, by having changes in the data.

    > memset(pBuffer,70,OUT_BUFFER_SIZE);
    6K of constant values is boring.
    Try filling it with random values, or maybe a chunk of a suitably encoded wav file.
    6000 values at 44100 values per second will give him about 0.13 seconds of sound... the very best he'll get from that is a click from the speaker.

    60,000 random values could produce a buzzing sound for about 1.3 seconds.

  5. #5
    and the hat of wrongness Salem's Avatar
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    Quite - in fact half that time, since the header specifies 16-bit samples.
    And half again, since the header specifies stereo output.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  6. #6
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    but I define OUT_BUFFER_SIZE,look:
    #define OUT_BUFFER_SIZE (44100*16*2/8*10)
    it has no voice,too.
    Why?

  7. #7
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    Quote Originally Posted by leetow2003 View Post
    but I define OUT_BUFFER_SIZE,look:
    #define OUT_BUFFER_SIZE (44100*16*2/8*10)
    it has no voice,too.
    Why?
    Tell me something... when you opened the wave output... exactly what did you expect to happen?

  8. #8
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    Quote Originally Posted by CommonTater View Post
    Tell me something... when you opened the wave output... exactly what did you expect to happen?
    I want to listen to voice,and when I
    #define OUT_BUFFER_SIZE (44100*16*2/8*10)
    I want to listen for 10 seconds,but I don't listen,
    why?

  9. #9
    and the hat of wrongness Salem's Avatar
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    Like I said - did you write in any valid PCM data or did you just fill it with a constant again?

    And I think it should be 44100 * 2 * 2 * 10

    That's nSamplesPerSec * nChannels * wBitsPerSample/8 * seconds.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  10. #10
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    Quote Originally Posted by leetow2003 View Post
    I want to listen to voice,and when I
    #define OUT_BUFFER_SIZE (44100*16*2/8*10)
    I want to listen for 10 seconds,but I don't listen,
    why?
    Ok let me ask my question one more time...

    EXACTLY what did you expect to happen when you opened the waveout?

    Did you expect it to just start talking?
    Last edited by CommonTater; 11-26-2011 at 09:29 AM.

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