Calling a function from within GDB

[joatmon]

I working in GDB to debug my program. At various breakpoints, I want to call a function that I wrote that iterates through my heap at that point in the execution. I have seen that I can call this function from within GDB like this:

(gdb) call foo()

But when I do, I get this error:

(gdb) call foo()
No symbol "foo" in current context.

The function clearly exists (and is called later on from within the program, and I know that I am not making any dumb mistakes like typos, but I don't know why it won't execute.

Am I calling this correctly? Is there somewhere that I can read about this problem? I've searched exhaustively in this, and it looks to me like this error is common for out-of-scope variables, but I don't see it explained with function calls. Maybe it thinks that I am looking for a variable? Very confused.

Thanks.

[manasij7479]

I don't know what you did but the following works for me.

#include<iostream>
using namespace std;
void foo()
{
    cout<<"How dare you call foo?"<<std::endl;
}
int main()
{

    return 0;
}

manasij7479@manasijd ~ $ g++ a.cpp -Wall -g
manasij7479@manasijd ~ $ gdb a.out
...
Reading symbols from /home/manasij7479/a.out...done.
(gdb) break 10
Breakpoint 1 at 0x8048643: file a.cpp, line 10.
(gdb) run
Starting program: /home/manasij7479/a.out

Breakpoint 1, main () at a.cpp:10
10 return 0;
(gdb) call foo()
How dare you call foo?
(gdb)

[joatmon]

Thanks. When I call other functions, it seems to work. There is something about the one that I am trying to call that isn't working out. Too much code to post here. I'm probably overlooking something.

[King Mir]

Maybe the function's inlined. Then you can't call it unless you turn that optimization off.

[joatmon]

It's not inlined. I got it to work by writing it in a different function. No idea why it worked in one place but not in the other. Thanks for your help.