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| | #16 | |
| Registered User Join Date: Dec 2006
Posts: 1,780
| Quote:
I would imagine it takes a lot of energy to melt the end of the screw driver and throw a guy across the room (heat makes gas rapidly expand?). Capacitors don't store a lot of energy. They just can discharge very quickly. Their energy density is a few orders of magnitude smaller than that of batteries. | |
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| | #17 |
| and the hat of sweating Join Date: Aug 2007 Location: Toronto, ON
Posts: 3,120
| The current they store is pretty small, but the voltage they can discharge is really high. Feel free to prove my teacher wrong, but I'll just take his word for it.
__________________ "I am probably the laziest programmer on the planet, a fact with which anyone who has ever seen my code will agree." - esbo, 11/15/2008 |
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| | #18 |
| Hail to the king, baby. Join Date: Oct 2008 Location: Faroe Islands
Posts: 713
| Reminds me of when I touched a open wire from a freezer, I just stood there shaking for a little while, like in movies and such xP But I have to say it was refreshing, most likely 'cause it gave me adrenaline |
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| | #19 |
| Registered User Join Date: Dec 2006
Posts: 1,780
| Well, current would depend on the equivalent impedance (resistance) of the load, and is really not up to the capacitor .It will just discharge faster, and the voltage will drop faster, if the current is higher (if you have infinite resistance, aka open circuit, and an ideal capacitor, it won't discharge at all), since for a capacitor, q = CV (where C is the capacitance, and q is charge stored), and delta_q = I*t. The total delivered energy will be the same (that's the conservation of energy). |
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| | #20 |
| and the hat of sweating Join Date: Aug 2007 Location: Toronto, ON
Posts: 3,120
| I haven't done anything with electronics since high school, so whatever you want to call it... The amount of electrons stored in the capacitor, or whatever.
__________________ "I am probably the laziest programmer on the planet, a fact with which anyone who has ever seen my code will agree." - esbo, 11/15/2008 |
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| | #21 | |
| C++ Witch Join Date: Oct 2003 Location: Singapore
Posts: 10,356
| Quote:
__________________ C + C++ Compiler: MinGW port of GCC Build + Version Control System: SCons + Bazaar Look up a C/C++ Reference and learn How To Ask Questions The Smart Way | |
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| | #22 | |
| Rampaging 35 Stone Welsh Join Date: Apr 2007
Posts: 2,926
| Quote:
Your teacher exaggerated his facts, but is correct in telling you a story that will scare you into not doing something stupid like sticking a screw driver into a PSU to see what would happen.
__________________ He is free, you say. Ah! That is his misfortune… These men… [have] the most terrible, the most imperious of masters, that is, need. … They must therefore find someone to hire them, or die of hunger. Is that to be free? - Simon Linguet | |
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| | #23 | |
| and the hat of sweating Join Date: Aug 2007 Location: Toronto, ON
Posts: 3,120
| Quote:
__________________ "I am probably the laziest programmer on the planet, a fact with which anyone who has ever seen my code will agree." - esbo, 11/15/2008 | |
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| | #24 |
| Hail to the king, baby. Join Date: Oct 2008 Location: Faroe Islands
Posts: 713
| No no, it means you stand shaking for awhile and smoke comes from your hair, then you get sent across the room and into a bar or something that would 'cause extra damage... Maybe also light a fire that interacts with some gas or fuel and then have a massive explosion... That's what Hollywood told me. |
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| | #25 | |
| Registered User Join Date: Dec 2006
Posts: 1,780
| The screw driver is a lower resistance path. Why would the current want to go through you? Even if it did, assuming the hand is 2 cm away from the conducting core of the screw driver (shortest air path), and air has a dielectric strength of ~2MV/m, the capacitor will need to be charged to about 40000V to cause a dielectric breakdown (air partially ionizes and starts conducting, like in lightning). And to melt, let's say, 1ml (8g) of steel, which has a heat capacity of ~500 J/kgK, heat of fusion of 247J/g, and melting point of 1500 degrees C. One would need (1500-20)*0.5*8 + 247*8 = 7896J. That is a lot of energy (the maximum power your outlet can put out without blowing the fuse, for 5 seconds). Quote:
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| | #26 |
| and the hat of sweating Join Date: Aug 2007 Location: Toronto, ON
Posts: 3,120
| This sounds like a job for Myth Busters.
__________________ "I am probably the laziest programmer on the planet, a fact with which anyone who has ever seen my code will agree." - esbo, 11/15/2008 |
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