is this right

[psycho88]

#include <stdio.h>

int main()

{
    
    int age;
    int name;
    
    printf( "enter your name" );
    scanf( "%d", name );
    if ( name == reece ) {
         printf( "wow thats my name aswell\n" );
         }
         else {
              printf( "you are &name\n" );
              }
         printf( "enter your age" );
         scanf( "%d", age );
         if ( age == 17 ) {
              printf( "wow I'm that age\n" );
              }
              else {
                   printf( "your name is &name\n" );
                   }
                   getchar();
                   reutnr 0;
                   }

i wrote this on my own, just for fun to see if it works but it gets an error on the if ( name == Reece ); line... ne suggestions on it?

and also is this the best way to write a code like?

[sunnypalsingh]

you can't compare strings like that...you need to use strcmp function of <string.h>

[SlyMaelstrom]

Yeah name is an integer not a string and reese isn't declared.

You'd want something like this:

char name[20];
scanf("%s", name);
if (strcmp(name, "Reese") == 0) {}

Look at this:
http://www.cprogramming.com/tutorial/lesson9.html

[psycho88]

thanks it works now.

but when i type something other than Reece, how do i get it to say, your name is "....." and same with age ?

+ when it says enter your name the thing u type starts right at the end of the sentance with no space.

[SlyMaelstrom]

else {
      printf( "You are %s\n", name );
}

[Salem]

Stop spamming the board with identical questions.