Count Number of Digits in and Integer

[redneon]

Does anyone know if it's possible to count the number of digits in an integer? One of my friends recommended log10 or something but I can't figure it out.

Redneon

[FillYourBrain]

the number of digits in a base 10 number is equal to the number of times you multiply 1 times 10 to get to the same length (plus one to account for the first digit). So essentially, log 10 is that number. your buddy is correct.

[Iamien]

Here you go should work as you need

  
int number,  temp, print;
cin>>number;

print = 0;
while (temp != 0) {

 temp = number % 10;
 number = number / 10;
 print++;
}
print = print -1; // reason for this below
cout<<print;

i forget why but for some reason when usign a while loop. the loop will execute one time after the specified stopping point
IE it would count one more then needed.
try it without this and you'll see what i mean