matching strings at end

[kurz7]

Hi guys,
Anyone see whats wrong here?
What im trying to do is input two strings say s and t.
Return true if the string s is at the end of string t.
My function just keeps return true.

cheers!

#include <stdio.h>
#include <string.h>
#define SIZE 1000

int strend( char [], char [] );
int main()
{
	char s[SIZE];
	char t[SIZE];
	printf( "Enter s: " );
	fgets( s, SIZE, stdin );
	printf( "Enter t: " );
	fgets( t, SIZE, stdin );

	if ( strend( s, t ) )
		printf( "string s occurs at end of string t\n" );
	else
		printf( "string s does not occur at the end of string t\n" );
	return 0;
}
int strend( char s[], char t[] )
{
	int i;
	int j;
	
	for ( i=strlen(t)-strlen(s); i<strlen(t)-2; ) {
		printf( "%d\n", i );
		for( j=0; j<strlen(s)-2; ) {
			if ( t[i] == s[j] )
			{
				i++;
				j++;
				break;
			}
			else {
			return 0;
			}
		}
	}
	return 1;
}

[Prelude]

>Anyone see whats wrong here?
Your doing it the hard way?

#include <string.h>

enum { NO, YES };

int strend(const char *s, const char *t)
{
    size_t slen = strlen(s);
    size_t tlen = strlen(t);
    int    rc;

    if (slen < tlen)
        rc = NO;
    else if (strcmp(s + (slen - tlen), t) == 0)
        rc = YES;
    else
        rc = NO;

    return rc;
}

Just check if the length of s is less than the length of t, if so s cannot contain t. Otherwise, subtract the length of t from the length of s and use that location as the first argument to strcmp. Boom! Instant strend logic with minimal effort on your part. The hardest part is to remember to check the lengths first.

[kurz7]

=(

forgot about strcmp

damnit

thanks guys!