let me go back to the original question on last time.
correct (yes/no)?
f(x)=abs(x-6)
y=abs(x-6)
x=abs(y-6)
either
x=-(y-6) if x<=6 then
6-x=f-1(x) if x<=6
Type: Posts; User: xddxogm3
let me go back to the original question on last time.
correct (yes/no)?
f(x)=abs(x-6)
y=abs(x-6)
x=abs(y-6)
either
x=-(y-6) if x<=6 then
6-x=f-1(x) if x<=6
it wasn't confusion from you, it is confusion from me not understanding in the first place.
in the problem it asks to find the inverse w/o graphing. i understand you need to restrict the domain to...
sorry to say this, but i'm a little more lost.
so let me see if i understand you correctly.
i assumed that since i was trying to acquire a function inverse it would be implied that i would be using a one to one function wich implies i would...
is this correct? (yes/no)
f(x) = abs (x-6)
x = abs (y-6)
abs (x+6) = y
abs (x+6) = f-1(x)